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Leviafan [203]
3 years ago
11

Which of the following is the point and slope of the equation y - 15 = -2(x + 1)?

Mathematics
2 answers:
Ghella [55]3 years ago
7 0

B. (-1, 15), -2

<u>y +/- y point = m/slope (x +/- x point)</u>


kari74 [83]3 years ago
5 0
The answer is letter B
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Have a test tomorrow, need help with question! Thank you :-)
Ket [755]
If 1/4x - 1/4 = 2 then 2 + 1/4 = 1/4x.
so 3/4 = 1/4x
3/4 is equal to 1/1.33 (reduce by dividing both numerator and denominator by 3)
so 4 x ? = 1.33. 1.33 / 4 = 0.3325
so (if you're solving for x) I believe the answer is x = 0.3325
8 0
3 years ago
What is the equation of a parabola with (−2, 4) as its focus and y = 6 as its directrix? Enter the equation in the box.
antiseptic1488 [7]

Check the picture below.  So the parabola looks more or less like so.

let's recall that the vertex is half-way between the focus point and the directrix, at "p" units away from both.

Let's notice that the focus point is below the directrix, that means the parabola is vertical, namely the squared variable is the "x", and it also means that it's opening downwards as  you see in the picture, namely that "p" is negative, in this case "p" is 1 unit, and thus is -1.

\bf \textit{parabola vertex form with focus point distance} \\\\ \begin{array}{llll} 4p(x- h)=(y- k)^2 \\\\ \stackrel{\textit{we'll use this one}}{4p(y- k)=(x- h)^2} \end{array} \qquad \begin{array}{llll} vertex\ ( h, k)\\\\ p=\textit{distance from vertex to }\\ \qquad \textit{ focus or directrix} \end{array} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \begin{cases} h=-2\\ k=5\\ p=-1 \end{cases}\implies 4(-1)(y-5)=[x-(-2)]^2\implies -4(y-5)=(x+2)^2 \\\\\\ y-5=-\cfrac{1}{4}(x+2)^2\implies y=-\cfrac{1}{4}(x+2)^2+5

6 0
3 years ago
HELPP!! I report wrong answers!!
Zarrin [17]
A : 12+1.5x=26 :))))
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3 years ago
I need help with homework these two problems I'm having trouble with
ycow [4]
The gcf of 25 and 60 is 5
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3 years ago
Which of the following is the correct solution to the linear inequality shown below?
Georgia [21]
Correct answer is C.

Line y=\frac{1}{3}x-2 intersects y-axis at -2 and passes through the point (3,-1).

Line must be dashed, because the inequality sign is ">".

Point (0,0) must lie in the solution set because it satisfies inequality y>\frac{1}{3}x-2.

0\ \textgreater \  \frac{1}{3}\times 0-2&#10;\\&#10;\\0\ \textgreater \ -2
5 0
3 years ago
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