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Aleonysh [2.5K]
3 years ago
5

How do you find a circumference of a circle?

Mathematics
1 answer:
Tanzania [10]3 years ago
5 0

Answer:The circumference = π x the diameter of the circle (Pi multiplied by the diameter of the circle). Simply divide the circumference by π and you will have the length of the diameter. The diameter is just the radius times two, so divide the diameter by two and you will have the radius of the circle!Hope it helps!!!!

Step-by-step explanation:

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Find the mean of the following data set.
nikklg [1K]

8+5+15+12+10= 50 / 5 = 10

5 0
3 years ago
Todd says that he can make 10 if he adds 32 coins to 28 coins. Is he correct? Explain how you know using words.
Andreas93 [3]
He was wrong, you cannot make 10 coins by adding 32 coins to 28 coins. If you want to obtain 10 coins from 32 coins and 28 coins, you can subtract 28 coins from 32 coins.
This can be illustrated as follows:
32-28=10
5 0
3 years ago
Kareem lives 4/10of a mile from the mall . write equivalent fractions that show what fraction of a mile karen lives from the mal
Slav-nsk [51]
You just have to simplify it by two 2/5 8/20

6 0
3 years ago
Please answer this for me pleaseeeee
kobusy [5.1K]

Answer:

\Huge\boxed{x=71.9}

Step-by-step explanation:

Hello There!

Once again we are going to use trigonometry to solve for x

Here are the <u>Trigonometric Ratios</u>

sin = opposite divided by hypotenuse

cos = adjacent divided by hypotenuse

tan = opposite divided by adjacent

we need to find x and we are given its opposite side length (58) and the adjacent side length (19)

this corresponds with tangent so once again we will be using tangent to solve for x

Looking at tangent we see that its equal to opposite divided by adjacent so we create an equation

tan(x)=\frac{58}{19}\\\frac{58}{19} =3.052631579

now we have

tan(x)=3.052631579

Once again we need to get rid of the tan

to do so we take the inverse of tan ( tan^-1) and apply it to each side

arcsin^-^1(tan(x))=x\\arcsin^-^1(3.052631579)=71.86191784

finally we round to the nearest tenth

we're left with x = 71.9

4 0
3 years ago
A certain town never has two sunny days in a row. Each day is classified as being either sunny, cloudy (but dry), or rainy. If i
11111nata11111 [884]

Answer:

the proportion of days that are Sunny is 0.2

Step-by-step explanation:

Given the data in the question;

Using markov chain;

3 states; Sunny(1), Cloudy(2) and Rainy(3)

Now, based on given conditions, the transition matrix can be obtained in the following way;

\left[\begin{array}{ccc}0&0.5&0.5\\0.25&0.5&0.25\\0.25&0.25&0.5\end{array}\right]

so let the proportion of sunny, cloudy and rainy days be S, C and R respectively.

such that, from column 1

S = 0.25C + 0.25R   -------------let this be equation 1

from column 2

0.5C = 0.5S + 0.25R

divided through by 0.5

C = S + 0.5R ---------------------- let this be equation 2

now putting equation 2 into equation;

S = 0.25(S + 0.5R) + 0.25R

S = 0.25S + 0.125R + 0.25R

S - 0.25S = 0.375R

0.75S = 0.375R

S = 0.375R / 0.75

S = 0.5R

Therefore,

from equation 2; C = S + 0.5R

input S = 0.5R

C = 0.5R + 0.5R

C = R

Now, we know that, the sum of the three proportion should be equal to one;

so

S + C + R = 1

since C = R and S = 0.5R

we substitute

0.5R + R + R = 1

2.5R = 1

R = 1/2.5

R = 0.4

Hence, the proportion of days that are Rainy is 0.4

C = R

C = 0.4

Hence, the proportion of days that are Cloudy is 0.4

S = 0.5R

S = 0.5(0.4)

S = 0.2

Hence, the proportion of days that are Sunny is 0.2

8 0
3 years ago
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