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3 years ago

Which relationship describes angles 1 and 2?

Mathematics

2 answers:

damaskus [11]3 years ago

8 0

1 and 2 two are:

a. adjacent angles
c. complementary angles

Answer is A and C

klasskru [66]3 years ago

3 0

They are complimentary angles because they add up to 90 degrees

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If C is the current value and S is the starting value, write an

LekaFEV [45]

Is there a diagram with this question?

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4 years ago

An empty box is shaped like a rectangular prism. the box has a base area of '9/10' square foot and a height of '1/3' foot. How m

maxonik [38]

Answer:3/10

Step-by-step explanation:

9 divided by 3 is 3 so that it

Next to 3/10 the denominator away stays the same,

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3 years ago

Can I please get some help with both problems

dimulka [17.4K]

So you subtract 180 from 90 you get you answer then you will divide it by 55 and your remaining answer which you will get will be x

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3 years ago

Karl is building a rectangular garden bed. The length is 6 feet. She has 20 feet of boards to make the sides. Write and solve an

natali 33 [55]

Answer:

The width of the garden bed must be less than or equal to 4 feet.

$w\leq4$

Explanation:

Given that;

She has 20 feet of boards to make the sides.

The perimeter of the garden bed must not be more than 20 feet

$\begin{gathered} P=2l+2w\leq20 \\ 2l+2w\leq20 \end{gathered}$

Given;

The length is 6 feet;

$l=6$

To get the inequality for the width w, let us substitute the value of the length into the inequality above and simplify;

$\begin{gathered} 2l+2w\leq20 \\ 2(6)+2w\leq20 \\ 12+2w\leq20 \\ 2w\leq20-12 \\ 2w\leq8 \\ \frac{2w}{2}\leq\frac{8}{2} \\ w\leq4 \end{gathered}$

Therefore, the width of the garden bed must be less than or equal to 4 feet.

$w\leq4$

8 0

1 year ago

Solve each system of equations; nonlinear algebra 2<br><br> x2 + x + y - 26 = 0<br> x + y = 1

BigorU [14]

Answer:

(5,-4) and (-5,6)

Step-by-step explanation:

Given:

$\left\{\begin{array}{l}x^2+x+y-26=0\\ \\x+y=1\end{array}\right.$

Solve it. First, express y in terms of x from the second equation:

$y=1-x$

Substitute it into the first equation:

$x^2+x+1-x-26=0\\ \\x^2-25=0\\ \\(x-5)(x+5)=0$

Apply zero product property:

$x-5=0\ \text{or}\ x+5=0$

So,

$x=5\ \text{or}\ x=-5$

When $x=5,$ then $y=1-5=-4$

When $x=-5,$ then $y=1-(-5)=6$

We get two solutions: (5,-4) and (-5,6)

8 0

3 years ago