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daser333 [38]
3 years ago
13

Which ordered pair describes a translation of 6 units up up and 4 units left

Mathematics
1 answer:
Aleksandr-060686 [28]3 years ago
4 0

Answer:

The correct answer for this is (-4,6).

Step-by-step explanation:

As it can be seen from the attached graph image:

  • The <em>y-axis </em><em>increases in positive</em> values when we move in up direction i.e. we have +<em>y-axis </em>in upward direction.
  • The <em>y-axis </em><em>decreases and keeps on becoming more and more negative</em> values when we move in down direction i.e. we have -<em>y-axis </em>in downward direction.
  • The <em>x-axis </em><em>increases in positive</em> values when we move in right direction i.e. we have <em>+x-axis </em>in right direction.
  • The x<em>-axis </em><em>decreases and keeps on becoming more and more negative</em> values when we move in left direction i.e. we have <em>-x-axis </em>in left direction.

Now, according to question, the translation is performed 6 points up i.e. towards positive y-axis and 4 points towards left i.e. towards negative x-axis.

And, as per rule, the co-ordinates are represented as (x,y) where x is the x-co-ordinate and y is y-co-ordinate.

So, the answer here is (-4,6).

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What is the GCF of (8x-6) <br><br>sos T-T
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Hi student, let me help you out! :)

. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .

We are asked to find the G.C.F. of 8x-6.

\triangle~\fbox{\bf{KEY:}}

  • G.C.F. stands for Greatest Common Factor.

So what is the G.C.F. of 8x-6? We can list all of their common factors and then select the greatest one, like so:

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\longmapsto\bf{Factors\;of\;-6:} -1, 1, 2, -3, 3, -6, 6

So the GCF is:

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Now, we can also factor it out by placing it outside the parentheses ():

2(4x-3)

See, we factored it out by dividing both terms of the expression by the G.C.F.

\ddot\bigstar Remember this...

\fbox{\bf{We\;factor\;out\;the\;G.C.F.\;by\;dividing\;all\;the\;terms\;of\;the\;expression\;by\;it}}

Hope this helps you out! :D

Ask in comments if any queries arise.

~Just a smiley person helping fellow students :)

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