Chris is standing due south of a 20m flagpole at a point where the angle of elevation of the top of the pole is 35. Brandyn is s
tanding due east of the flagpole at a point where the angle of elevation of the top of the pole is 27. How far is Brandyn from Chris?
1 answer:
Answer:
Brandyn is 41.48m from Chris
Step-by-step explanation:
I have drawn an image depicting this question and I've attached it.
From the diagram, chris is standing at point B while Brandyn is at point D. x is the distance of brandyn to the bottom of the pole.
The height of the pole is AC.
Now, by trigonometric ratio, we can find AC. Thus;
AC/20 = tan 35
AC = 20 tan 35
AC = 14
Since,we now have AC, we can find x.
Similarly, 14/x = tan 27
x = 14 / tan 27
x = 27.48 m
Thus, total distance of brandyn from Chris = 14 + 27.48 = 41.48 m
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Answer:
hey hope this helps
<h3 /><h3>Comparing sides AB and DE </h3>AB =
DE
So DE = 2 × AB
and since the new triangle formed is similar to the original one, their side ratio will be same for all sides.
<u>scale factor</u> = AB/DE
= 2
It's been reflected across the Y-axis
<em>moved thru the translation of 3 units towards the right of positive x- axis </em>
for this let's compare the location of points B and D
For both the y coordinate is same while the x coordinate of B is 0 and that of D is 3
so the triangle has been shifted by 3 units across the positive x axis