Chris is standing due south of a 20m flagpole at a point where the angle of elevation of the top of the pole is 35. Brandyn is s
tanding due east of the flagpole at a point where the angle of elevation of the top of the pole is 27. How far is Brandyn from Chris?
1 answer:
Answer:
Brandyn is 41.48m from Chris
Step-by-step explanation:
I have drawn an image depicting this question and I've attached it.
From the diagram, chris is standing at point B while Brandyn is at point D. x is the distance of brandyn to the bottom of the pole.
The height of the pole is AC.
Now, by trigonometric ratio, we can find AC. Thus;
AC/20 = tan 35
AC = 20 tan 35
AC = 14
Since,we now have AC, we can find x.
Similarly, 14/x = tan 27
x = 14 / tan 27
x = 27.48 m
Thus, total distance of brandyn from Chris = 14 + 27.48 = 41.48 m
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<u>Given:</u>
The angle of elevation from the point on the ground to the top of the tree is 34° and the point is 25 feet from the base of the tree.
We need to determine the height of the tree.
<u>Height of the tree:</u>
Let the height of the tree be h.
The height of the tree can be determined using the trigonometric ratio.
Thus, we have;
Substituting the values, we get;
Multiplying both sides by 25, we have;
Rounding off to the nearest tenth of a foot, we get;
Thus, the height of the tree is 16.9 feet.
Hence, Option B is the correct answer.