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Colt1911 [192]
3 years ago
5

Lucy spends 4 hours a week babysitting. Her sister Lily spends seven eighths as much time babysitting. Does Lily babysit for mor

e or less than 4 hours.
Mathematics
1 answer:
olganol [36]3 years ago
4 0

Answer:

Lily babysit for <u>less than 4 hours</u>.

Step-by-step explanation:

Given:

Lucy spends in a week babysitting for 4 hours.

Lily spends seven-eighths of 4 hours.

Now, to find whether Lily babysit for more than 4 hours or less than that.

Number of hours Lucy babysit = 4 hours.

So, to get the hours Lily babysit:

\frac{7}{8}\ of\ 4\ hours.

=\frac{7}{8}\times 4\\\\=\frac{28}{8} \\\\

<em>On simplifying we get:</em>

=\frac{7}{2} \\\\=3\frac{1}{2}\ hours.

<u><em>Thus, Lily spends </em></u>3\frac{1}{2}\ hours<u><em>  for babysitting which is less than 4 hours.</em></u>

Therefore, Lily babysit for less than 4 hours.

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Subtract the rational expression 1/x^2-x-6 - x/x+2.
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Step-by-step explanation:

x² - x -6 = x²  + 2x - 3x - 3*2

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\frac{1}{x^{2}-x-6}+\frac{x}{x+2}=\frac{1}{(x +2 )(x - 3)}-\frac{x}{x + 2}\\

                      = \frac{1}{(x+2)(x-3)}-\frac{x(x-3)}{(x+2)(x-3)}\\\\=\frac{1-x(x-3)}{(x+2)(x-3)}\\\\=\frac{1-x^{2}+3x}{(x+2)(x-3)}\\\\

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2 years ago
16. A rock weighs 6 and 1/2 tons. How many pounds does the rock weigh?<br> 2,000 lb = 1 T
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13000

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Solve 37+z≤54. Graph the solution.
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z ≤ 17

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Suppose you draw a card from a well-shuffled deck of 52 cards. Find each of the following odds.
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<em>Add 3 on both sides of the equation.</em>

-3-5y+3=12-2y+3-5y=15-2y

<em>Add 2y on both sides of the equation.</em>

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Answer:

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<em />

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