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Colt1911 [192]
3 years ago
5

Lucy spends 4 hours a week babysitting. Her sister Lily spends seven eighths as much time babysitting. Does Lily babysit for mor

e or less than 4 hours.
Mathematics
1 answer:
olganol [36]3 years ago
4 0

Answer:

Lily babysit for <u>less than 4 hours</u>.

Step-by-step explanation:

Given:

Lucy spends in a week babysitting for 4 hours.

Lily spends seven-eighths of 4 hours.

Now, to find whether Lily babysit for more than 4 hours or less than that.

Number of hours Lucy babysit = 4 hours.

So, to get the hours Lily babysit:

\frac{7}{8}\ of\ 4\ hours.

=\frac{7}{8}\times 4\\\\=\frac{28}{8} \\\\

<em>On simplifying we get:</em>

=\frac{7}{2} \\\\=3\frac{1}{2}\ hours.

<u><em>Thus, Lily spends </em></u>3\frac{1}{2}\ hours<u><em>  for babysitting which is less than 4 hours.</em></u>

Therefore, Lily babysit for less than 4 hours.

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Answer:

t=\frac{8.19-9.02}{\frac{0.8}{\sqrt{17}}}=-4.28    

The degrees of freedom are given by

df=n-1=17-1=16  

The p value would be given by this probability:

p_v =P(t_{(16)}  

Since the p value is lower than the significance level provided of 0.01 we have enough evidence to reject the null hypothesis and we can conclude that the true mean is significantly lower than 9.02 cm^3

Step-by-step explanation:

Information given

\bar X=8.19 cm^3 represent the sample mean

s=0.8 cm^3 represent the sample deviation

n=17 sample size  

\mu_o =9.02 represent the value to verify

\alpha=0.01 represent the significance level for the hypothesis test.  

t would represent the statistic

p_v represent the p value

System of hypothesis to check

We want to check if the true mean is less than the normal value of 9.02 cm^3, the system of hypothesis would be:  

Null hypothesis:\mu \geq 9.02  

Alternative hypothesis:\mu < 9.02  

The statistic for this case is given by:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

Replacing the info given we got:

t=\frac{8.19-9.02}{\frac{0.8}{\sqrt{17}}}=-4.28    

The degrees of freedom are given by

df=n-1=17-1=16  

The p value would be given by this probability:

p_v =P(t_{(16)}  

Since the p value is lower than the significance level provided of 0.01 we have enough evidence to reject the null hypothesis and we can conclude that the true mean is significantly lower than 9.02 cm^3

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Answer:

I will be needing a picture for this question. However, here is a formula to help you out! y2-y1/x2-x1    (the Xs are on the bottom, and the Ys are on the top. Pick an 2 ordered pairs, and then put them like the formula. X2  and Y2 are an ordered pair, same for X1 and Y1.) Hope this helped ;)

Step-by-step explanation:

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3 years ago
Thank u for answering !​
maxonik [38]

Answer:

1. C

2. A

3. B

4. B

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6. A

Step-by-step explanation:

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