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4 years ago

Simplify the expression: 6 + 8j - 9j + -5j - 3

1 answer:

8 0

So first you’ll combine the J’s.
8j - 9j = 1j
+ -5j
Which will be -4j.
That makes: 6 + -4j - 3
So you can subtract 6-3 to make 3.
Which makes 3 + -4j
That’s the answer!

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(Refer to the attached image)

RSB [31]

Answer:

missing side: 133 cm

Explanation:

Provided 2 length sides and one angle also need to find one missing side.

So, use cosine rule:

⇒ a² = b² + c² - 2bc cos(A)

Insert values

⇒ g² = 166² + 147² - 2(166)(147) cos(50)

⇒ g² = 17794.3935

⇒ g = √17794.3935

⇒ g = 133.3956

⇒ g = 133 (rounded to nearest whole number)

8 0

2 years ago

A^3b^-2c^-1d if a=2 b=4 c=10 d=15 express as a reduced fraction

Juli2301 [7.4K]

Answer:

Don't know if this is correct but, I think the answer is 3/4.

5 0

3 years ago

Read 2 more answers

Me. Ellis is a teacher who tutors after school. Of the students he tutors, 30% need help in computer science and 70% need assist

Anna11 [10]

Answer: There are 82.5% after school students who are enrolled in his classes.

Step-by-step explanation:

Let the total number of students be 100

Percentage of students who need help in computer science = 30%

So, number of students who need help in computer science = 30

Percentage of students who need help in maths = 70%

So, number of students who need assistance in maths = 70

Of the students who need help,

40% are enrolled in Mr. Ellis's class during the school day,

So, it means 60% are enrolled in his class after the school day.

Number of students who are enrolled in his class after the school day = 60

Number of students who need help in Maths is given by

$\frac{70}{100}\times 60=42$

Of the students that need help in maths, percent of students are enrolled in his class during the day = 25%

So, number of students who need help in maths and enrolled in his class after school hours

$\frac{75}{100}\times 42=31.5$

Number of students who need help in computer science and enrolled in his class after school hours

$\frac{30}{100}\times 60=18$

Therefore, there are $31.5+18=49.5$ students who joined his class after school hours,

Percentage of the after students who are enrolled in Mr. Ellis's classes is given by

$\frac{49.5}{60}\times 100=82.5\%$

Hence, there are 82.5% after school students who are enrolled in his classes.

6 0

4 years ago

9) 14 pounds to 63 pounds

meriva

Answer:

What is the question?

Step-by-step explanation:

8 0

4 years ago

A carnival costs $10.50 to enter plus an additional $3.50 per ticket for rides and food.

Goryan [66]

Answer:

$\$80.50$

Step-by-step explanation:

Let

n ----> represent the number of tickets purchased

y ---> the total cost for a visit to the carnival in dollars

we know that

The linear equation in slope intercept form is equal to

$y=m(n)+b$

where

m is the slope or unit rate of the linear equation

b is the y-intercept or initial value

In this problem we have

The unit rate or slope is equal to

$m=\$3.50\ per\ ticket$

The y-intercept is equal to the cost for enter (value of y when the value of x is equal to zero)

$b=\$10.50$

substitute

$y=3.50(n)+10.50$

For n=20 tickets

substitute the value of n and solve for y

$y=3.50(20)+10.50$

$y=\$80.50$

5 0

3 years ago