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nevsk [136]
3 years ago
6

Evaluate (13+2) Divided by(9-4)

Mathematics
2 answers:
DIA [1.3K]3 years ago
7 0
13+2=15
Then
9-4=5
Then divide it your answer is 3
Because 15 divide by 5 is 3
skelet666 [1.2K]3 years ago
6 0

Answer:

=3

Step-by-step explanation:

following the order of operations, whatever is in the parentheses gets done first. so you would add 13 + 2 and get 15. then you would subtract 9-4 and get 5. then you would divide the numbers that you got and get 3.

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<em>Given, 9−7x=5−3x</em>

<em>Given, 9−7x=5−3xPut x terms on one side and constants on another side.</em>

<em>Given, 9−7x=5−3xPut x terms on one side and constants on another side.⇒9−5=7x−3x</em>

<em>Given, 9−7x=5−3xPut x terms on one side and constants on another side.⇒9−5=7x−3x⇒4=4x</em>

<em>Given, 9−7x=5−3xPut x terms on one side and constants on another side.⇒9−5=7x−3x⇒4=4x⇒x= </em><em>4</em><em>/</em><em>4</em><em> </em><em> =1</em>

<em> =1Hence, required solution is x=1.</em>

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(3,7) Quadrant where the point is located
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A problem states: "There are 9 more pencils than pens in a container. There are 25 writing utensils in the container in all. How
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Leokris [45]

Substitute v(x)=-2x+y(x), so that \dfrac{\mathrm dv}{\mathrm dx}=-2+\dfrac{\mathrm dy}{\mathrm dx}. Then the ODE is equivalent to

\dfrac{\mathrm dv}{\mathrm dx}+2=v^2-7

which is separable as

\dfrac{\mathrm dv}{v^2-9}=\mathrm dx

Split the left side into partial fractions,

\dfrac1{v^2-9}=\dfrac16\left(\dfrac1{v-3}-\dfrac1{v+3}\right)

so that integrating both sides is trivial and we get

\dfrac{\ln|v-3|-\ln|v+3|}6=x+C

\ln\left|\dfrac{v-3}{v+3}\right|=6x+C

\dfrac{v-3}{v+3}=Ce^{6x}

\dfrac{v+3-6}{v+3}=1-\dfrac6{v+3}=Ce^{6x}

\dfrac6{v+3}=1-Ce^{6x}

v=\dfrac6{1-Ce^{6x}}-3

-2x+y=\dfrac6{1-Ce^{6x}}-3

y=2x+\dfrac6{1-Ce^{6x}}-3

Given the initial condition y(0)=0, we find

0=\dfrac6{1-C}-3\implies C=-1

so that the ODE has the particular solution,

\boxed{y=2x+\dfrac6{1+e^{6x}}-3}

5 0
3 years ago
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