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3 years ago

What is the measure of angle BCD? Please helppppp

Mathematics

2 answers:

Vlada [557]3 years ago

7 0

It's 135, hope it helps <3

mojhsa [17]3 years ago

5 0

the right answer is 135

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Please help if i get this wrong i will fail

LUCKY_DIMON [66]

The answer is either b or c

3 0

3 years ago

Read 2 more answers

Jim drank 245 cups of orange juice and Jack drank 1110 cups less than Jim.

Debora [2.8K]

Answer:

Step-by-step explanation:

Jim drank 2 and 4/5 orange juice

2and 4/5=14/5 orange juice

jack drank 1and 1/10 less than Jim= 11/10 less than Jim

I introduce the whole numbers into the fractions

we will convert the number 14/5 into a fraction that has the denominator 10, by multiplying by 2 both numerator and denominator

(14/5 )*2=28/10

Now we can find out how much juine Jack drank

28/10- 11/10= 17/10

so Jack drank 17/10 orange juice , the fraction can be written also as

1 and 7/10

5 0

2 years ago

(1Q) Describe how to transform the graph of g(x) = lnx into the graph of f(x)= ln(x-4)+3?

xxMikexx [17]

Answer:

Step-by-step explanation:

The correct answer is to go 4 units right (the direction is opposite to the sign) and 3 units up. The up and down direction is the same number as after the function.

Red: Parent Function y = ln(x)

Blue: 4 units right. 3 units up.

Answer: B

6 0

3 years ago

Find all solutions of each equation on the interval 0 ≤ x < 2π.

Korvikt [17]

Answer:

$x = 0$ or $x = \pi$ .

Step-by-step explanation:

How are tangents and secants related to sines and cosines?

$\displaystyle \tan{x} = \frac{\sin{x}}{\cos{x}}$ .

$\displaystyle \sec{x} = \frac{1}{\cos{x}}$ .

Sticking to either cosine or sine might help simplify the calculation. By the Pythagorean Theorem, $\sin^{2}{x} = 1 - \cos^{2}{x}$ . Therefore, for the square of tangents,

$\displaystyle \tan^{2}{x} = \frac{\sin^{2}{x}}{\cos^{2}{x}} = \frac{1 - \cos^{2}{x}}{\cos^{2}{x}}$ .

This equation will thus become:

$\displaystyle \frac{1 - \cos^{2}{x}}{\cos^{2}{x}} \cdot \frac{1}{\cos^{2}{x}} + \frac{2}{\cos^{2}{x}} - \frac{1 - \cos^{2}{x}}{\cos^{2}{x}} = 2$ .

To simplify the calculations, replace all $\cos^{2}{x}$ with another variable. For example, let $u = \cos^{2}{x}$ . Keep in mind that $0 \le \cos^{2}{x} \le 1 \implies 0 \le u \le 1$ .