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mart [117]
3 years ago
5

Find all real zeros of the function y = -7x+8.

Mathematics
2 answers:
Shtirlitz [24]3 years ago
7 0

Answer:

A) 8/7

Step-by-step explanation:

RSB [31]3 years ago
5 0

Answer:

A) 8/7

Step-by-step explanation:

y=0

0=-7x+8

-8=-7x

8/7=x

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Find the most common ratio 72,12,2, 1/3,1/18
liraira [26]

Answer:

1/6

Step-by-step explanation:

To find the common ratio, you compare a few pairs of consecutive terms, by dividing an element by its predecessor.

12 / 72 = 1/6

2 / 12 = 1 / 6

1/3 / 2 = 1 / 6

The ratio is constant... so that's your common ratio to go from one term to the next.  

To go from one term to the next, you have to multiply by 1/6.

7 0
3 years ago
4/5G + 42 = 2.8G + 18<br> Plz solve with an explanation
inysia [295]

Answer:

12

Step-by-step explanation:

Simplify  \frac{4}{5}G

​5

​

​4

​​ G  to  \frac{4G}{5}

​5

​

​4G

​​ .

\frac{4G}{5}+42=2.8G+18

​5

​

​4G

​​ +42=2.8G+18

Multiply both sides by 5.

4g + 210 = 14g + 90

Simplify  

 14G + 90 - 4G to 10G + 90

Subtract 90 from both sides.

210-90=10G210−90=10G

Simplify  210-90210−90  to  120120.

120=10G120=10G

Divide both sides by 1010.

\frac{120}{10}=G

​10

​

​120

​​ =G

Simplify  \frac{120}{10}

​10

​

​120

​​   to  1212.

12=G12=G

Switch sides.

G=12G=12

SORRY ABOUT ALL THIS WORK...

3 0
3 years ago
Read 2 more answers
A mass weighing 3 lb stretches a spring 3 in. If the mass is pushed upward, contracting the spring a distance of 1 in and then s
Bas_tet [7]

Answer:

Step-by-step explanation:

m=\frac{3}{32}\\ \gamma =0\text{ damping constant.}\\ k=\frac{3}{\frac{1}{4}}=12\\ F(t)=0\\ \text{so equation of motion is }\\ mu''+\gamma u'+ku=F(t)\\ \frac{3u''}{32}+12u=0\\ u''+128u=0\\ \text{and initial conditions are}\\ u(0)=-\frac{1}{12}\\ u'(0)=2\\ u''+128u=0\\ \text{characterstic equation is}\\ r^2+128=0\\ \text{roots are }\\ r=\pm 8\sqrt{2}i\\ \text{therefore general solution is}\\ u(t)=A\cos8\sqrt{2}t+Bsin8\sqrt{2}t\\ \text{using initial conditions we get}\\ A=-\frac{1}{12}\\ B=\frac{\sqrt{2}}{8}\\ \text{therefore solution is }\\ u(t)=-\frac{1}{12}\cos8\sqrt{2}t+\frac{\sqrt{2}}{8}\sin8\sqrt{2}t\\&#10;{hence}\\R=\sqrt{\frac{11}{288}}\\\\\sigma=\pi - \tan^{-1}\frac{1}{\sqrt{2}}\\\\\omega_0=8\sqrt{2}\\T=\frac{4}{4\sqrt{2}}

3 0
3 years ago
Can anyone help me out in my homework. I would love to talk about these problems ​
katen-ka-za [31]

Step-by-step explanation:

(b) If F_G = m_1g, then

m_1g = G\dfrac{m_1m_2}{r^2}

Note that m_1 cancel out so we get

g = G\dfrac{m_2}{r^2}

Solving for m_2, we get

m_2 = \dfrac{gr^2}{G}

(c) I'm not sure what the problem is asking for but here goes. As r doubles, F_G becomes

F_G = G\dfrac{m_1m_2}{(2r)^2} = \dfrac{1}{4}\left(G\dfrac{m_1m_2}{r^2}\right)

5 0
3 years ago
Need the answer NOW plz help me!!
Dovator [93]

The answer is (7,2) and 45 units squared.

See attached picture.

6 0
4 years ago
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