The figure below shows a diagram of this problem. First of all we graph the hemisphere. This one has a radius equal to 1. Given that z ≤ 0 a sphere will be valid only in the negative z-axis, that is, we will get a half of a sphere that is the hemisphere shown in the figure. We know that this hemisphere is oriented by the inward normal pointing to the origin, then we have a Differential Surface Vector called
N, using the Right-hand rule <span>the boundary orientation is </span>counterclockwise.
Therefore, the answer above
False
The volume of a cylinder is 
- r is the radius (half of the diameter which is 34m) --> 17m
- height: 27m
: 3.14
Thus the volume = 
Hope that helped!
Think: "Find <span>tan-1(0.577)" means "Find the ANGLE in Quadrant III whose tangent is 0.577. Because the angle is in QIII, both the opp side and the adj side are negative. Here you have four answer choices. The correct answer MUST be within the interval 180 and 270 degrees. Only one of the given answer choices satisfies that criterion. Which one is it?
</span><span>tan-1(0.577) = ?</span>
Answer:
y = (1/2)x + 1
Step-by-step explanation:
linear line equation is y = mx + b
Where m is the slope and b is the y-intercept when x is 0.
For m, m is change in y(delta y) over change in x(delta x).
We are given two points: (0,1) and (4,3).
m = (y2 - y1)/(x2 - x1) = (3-1)/(4-0) = 2/4 = 1/2
y = (1/2)x + b
Now plug in (0,1) into above equation to find b value.
1 = (1/2)0 + b => b = 1
Final equation is y = (1/2)x + 1
Mes ∠AKG = mes ∠AKD + mes ∠ DKG
133° = mes ∠ AKD + 87°
133° - 87° = mes ∠AKD
∠AKD = 46°
