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Naily [24]
3 years ago
15

Https://cook.owschools.com/media/g_alg02_ccss_2016/4/q16210.gif

Mathematics
1 answer:
labwork [276]3 years ago
3 0
Im assuming your supposed to find like terms soo... as my final answer i got 11m-3n-13
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A spinner is divded into two equally sized sections. The sections are labeled STOP and GO. S represents STOP and G represents GO
krek1111 [17]

Answer:

The sample space is SG,GG,SS,GS. I know this because the sample space is the set of all possible outcomes of an experiment.

Hope this helped!

7 0
2 years ago
Read 2 more answers
Pls help me I don’t understand
ipn [44]

Answer:

m<PXQ Is Acute

m<QXN is Obtuse

Step-by-step explanation:

Acute Angles are lsss than 90⁰

Obtuse Angles are greater than 90⁰

Right angles are exactly 90⁰

6 0
3 years ago
Can somebody help me out?<br><br> s/4<br> ? = 4
Yuki888 [10]

Answer:

If you are asking S/4=4 (as in what does S equal) the answer is 16

Step-by-step explanation:

4x4= 16

so 16/4=4 :)

7 0
3 years ago
Aidan has $7565 in his checking account. He invests it in an account that earns 3.5% interest compounded continuously. What is t
Fudgin [204]
Total amount = Pe^(rt)
where
P=principal
e=2.7182818284...
r=0.035
t=3 (years)

Total amount
= 7565(e^(0.035*3)
=$ 8402.53
7 0
2 years ago
can someone pls help me? i have no idea what to do. pls show the work steps for the questions. i will mark u as
tiny-mole [99]

Ok, so the question is based on geometric progression. Remember, the formula for calculating the nth-term of a geometric progression is: a*r^{n-1}. The a in the expression stands for the 1st term of the sequence, and r is the common ratio of the elements of the sequence. Now let's take a look at the problem.

"A ping pong ball has a 75% rebound ration". We can infer that our common ratio, r, is 75% which is 0.75.

"When you drop it from a height of k feet...", this means the first height you drop it from, a.k.a, the first term.

Now going back to the expression, the nth-term = a*r^{n-1}, we can substitute our common ration, 0.75 with r, and our 1st term, k, with a. This becomes: k * 0.75^{n-1}. This becomes our expression.

a. The highest height achieved by the ball after six bounces. Our nth-term here is 6, so let's use our expression to find the 6th term. n_{6} = 235 * 0.75^{6-1} = 235*0.75^{5} = 235*0.2373 = 55.7655ft

b. The total distance travelled by the ball when it strikes the ground for the 12th time. This involves the use of the sum of elements in the geometric progression. The formula for that is \frac{a(1 - r^{n})}{1-r}, provided that r is less than 1, which it is in this case, since 0.75 is less than one. Our nth-term here is 12, so we substitute.

\frac{235(1-0.75^{12})}{(1-0.75)} = 910.2242ft

6 0
2 years ago
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