Answer:
Rational form:
399/100 = 3 + 99/100
Continued fraction:
[3; 1, 99]
Possible closed forms:
399/100 = 3.99
log(54)≈3.988984
8/(3 π) + π≈3.9904190
1/2 (e! + 1 + e)≈3.989551
-(sqrt(3) - 3) π≈3.983379
(14 π)/11≈3.9983906
25/(2 π)≈3.978873
(81 π)/64≈3.976078
(2 e^2)/(1 + e)≈3.974446
(π π! + 2 + π + π^2)/(3 π)≈3.988765
2 π - log(4) - 3 log(π) + 2 tan^(-1)(π)≈3.987955
2 - 1/(3 π) + (2 π)/3≈3.988291
Step-by-step explanation:
Answer:
23 years
Step-by-step explanation:
Step 1: Calculate the rate constant (k) for the radioactive decay
A radioactive substance with initial concentration [A]₀ decays to 97% of its initial amount, that is, [A] = 0.97 [A]₀, after t = 1 year. Considering first-order kinetics, we can calculate the rate constant using the following expression.
ln [A]/[A]₀ = - k.t
k = ln [A]/[A]₀ / -t
k = ln 0.97 [A]₀/[A]₀ / -1 year
k = 0.03 year⁻¹
Step 2: Calculate the half-life of the substance
We will use the following expression.
= ln2/ k = ln 2 / 0.03 year⁻¹ = 23 years
Total number of Bananas = 18
Number of Bananas that are left = 10
Percentage of Bananas that are left = x
Mathematically, x can be expressed as:

Thus the correct percentage of number of bananas that are left is expressed by option c.