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Oksana_A [137]
3 years ago
15

Two points, (-2,4) and (2,4), are plotted on a coordinate grid.

Mathematics
1 answer:
LekaFEV [45]3 years ago
6 0

Answer:

Step-by-step explanation:

Given the coordinate points  (-2,4) and (2,4), the expression to calculate the distance between the points is expressed as:

D = √(x2-x1)²+(y2-y1)²

From the coordinates;

x1 = -2, y1 = 4, x2 = 2 and y2 = 4

Substitute

D = √(2-(-2))²+(4-4)²

D = √(4)²+(0)²

D = √16

D = 4

The distance between the two points is 4 and the expression used is D = √(2+2))²+(4-4)²

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EleoNora [17]

Answer: No solutions

Step-by-step explanation: If you solve the problem all the way, you get 0 = 4 which is not valid so there is simply no solution

8 0
3 years ago
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Please help me with the below question.
tresset_1 [31]

We have the following three conclusions about the <em>piecewise</em> function evaluated at x = 14.75:

  1. \lim_{t \to 14.75^{-}} f(t) = 66.
  2. \lim_{t \to 14.75^{+}} f(t) = 10.
  3. \lim_{t \to 14.75} f(t) does not exist as \lim_{t \to 14.75^{-}} f(t) \ne  \lim_{t \to 14.75^{+}} f(t).

<h3>How to determinate the limit in a piecewise function</h3>

In a <em>piecewise</em> function, the limit for a given value exists when the two <em>lateral</em> limits are the same and, thus, continuity is guaranteed. Otherwise, the limit does not exist.  

According to the definition of <em>lateral</em> limit and by observing carefully the figure, we have the following conclusions:

  1. \lim_{t \to 14.75^{-}} f(t) = 66.
  2. \lim_{t \to 14.75^{+}} f(t) = 10.
  3. \lim_{t \to 14.75} f(t) does not exist as \lim_{t \to 14.75^{-}} f(t) \ne  \lim_{t \to 14.75^{+}} f(t).

To learn more on piecewise function: brainly.com/question/12561612

#SPJ1

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Step-by-step explanation:

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3 years ago
Solve the equation. Then check your solution.
Arte-miy333 [17]

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Move +5 to the other. Sign changes from +5 to -5.

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Answer : x= 8

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3 years ago
Complete the equation below to show a way to write 5/38 as a fraction
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5/38 is 0.13 because you have to divide them
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