How do i find the area of a trapazoid

50 POINTS AND WILL MARK BRAINLIEST NEED HELP ASAP

trasher [3.6K]

Answer:

Please see attached image and all steps below for both parts

Step-by-step explanation:

Task 1

The following system of equations includes a linear equation and a quadratic one:

$\left \{ {{y=x+2} \atop {y=x^2-8x+2}} \right} \}$

it can be solved by using substitution in the second equation of the variable "y" by the linear expression of the first equation:

$x+2=x^2-8x+2\\x=x^2-8x\\x^2-9x=0\\x\,(x-9)=0$

and this product of two factors will e zero when either factor is zero, that is: when x = 0, or when x = 9 [to make zero the binomial(x - 9)]

There are two solutions: x = 0 and x = 9.

When we graph both expressions in the system, we see that the line intercepts the parabola at the points (0, 2) and (9, 11). See attached image.

Task 2

Part 1:

Let's pick 30 as a number larger than 25. 30 can be written as 40 - 10

So we can use:

$(40 -10)^2=40^2-2\,(40)\,(10)+ 10^2=1600-800+100=900$

to calculate its square.

Part 2:

let's choose a=9 and b=10 so we use:

$9^3+10^3=(9 + 10)\,(9^2-(9)\,(10)+10^2)=(19)\,(81-(90)+100)=19\,(81-180+100)=19\,*\,91=1729$

8 0

3 years ago

Lucy and Kareem each opened a savings account today. Lucy opened her account with a starting amount of $160, and she is going to

Leto [7]

I'm doing the same one right now lol, also if anyone gives you a link , don't open it . it can be a hacker . Step-by-step explanation:

4 0

3 years ago

Help pleaseeeeeeeeeeeeeeeeeee

Elenna [48]

Answer:

D

Step-by-step explanation:

5 0

3 years ago

C=48y+0.99n solve for y

Ne4ueva [31]

Answer:

y = (C -0.99n)/48

Step-by-step explanation:

Undo what is done to y, in the reverse order. We have y multiplied by 48 then added to 0.99n. So, we must add the opposite of 0.99n and multiply that result by the reciprocal of 48.

C = 48y + 0.99n . . . . . . given

C - 0.99n = 48y . . . . . . add -0.99n

(C -0.99n)/48 = y . . . . . multiply by 1/48

4 0

4 years ago

Pls answer the question attached

barxatty [35]

$\huge\mathfrak{\underline{answer:}}$

$\large\bf{\angle ACD = 105°}$

__________________________________________

$\large\bf{\underline{Here:}}$

BCD is an isosceles right triangle , right angled at D
ABC is an equilateral triangle

$\large\bf{\underline{To\:find:}}$

∠ ACD

$\large\bf{In\: triangle\:ABC:}$

❒ Sum of all angles is 180° , since it is an equilateral triangle all the three angles would be same

$\large\bf{\underline{So}}$

‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎ $\bf{⟼\angle ACB = \frac{180}{3}}$

‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎ $\bf{⟼\angle ACB = 60°}$

$\large\bf{In\: triangle\:BDC}$

‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎ $\bf{⟼\angle D = 90°}$

$\bf{⟼\angle DBC =\angle DCB }$ (Isosceles triangle)

‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎ $\bf{⟼\angle DBC + \angle BDC + \angle DCB = 180° }$

‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎ $\bf{⟼2\angle DCB + 90° = 180°}$

‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎ $\bf{⟼2\angle DCB = 180 -90}$

‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎ $\bf{⟼\angle DCB = \frac{90}{2}}$

‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎ $\bf{⟼\angle DCB = 45°}$

$\large\bf{\underline{Therefore,}}$

‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎ $\bf{⟹\angle ACD = \angle ACB + \angle DCB}$

‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎ $\bf{⟹\angle ACD = 60+45}$

‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎ $\large\bf{⟹\angle ACD = 105°}$

6 0

3 years ago

How do i find the area of a trapazoid ​

How do i find the area of a trapazoid