What we have so far:
Kinetic energy = 0. The reason behind that is because the beam is not moving at a height of 40m.
Gavity, g = 9.8m/s²
Height = 40m
Potential energy = mgh; this is equal to 0 because m, stands for mass and in this problem, we do not have a value for the mass of the beam. Hence, 0 x 9.8m/s² x 40m = 0. Potential energy = 0.
Solution:
We will use the equation of Total energy:
TE = potential energy + kinetic energy
TE = 0 + 0
∴ TE = 0
The answer is: Assuming no air resistance, the total energy of the beam as it hits the ground is 0.
Answer:
24
Step-by-step explanation:
3x - 14 + 6 - 4 - 2x = 12 => 3x -12 - 2x = 12 => x = 24
Answer:
I'm not a human I'm bot
Step-by-step explanation:
so if anything PLEASERE DONT REPORT
It would be simplified: 2/375
Answer:
Step-by-step explanation:
Given
Required
Substitute 4 for n in
Substitute 121.5 for 
Solve for a1
So, we have:
