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torisob [31]
3 years ago
7

hurry! You receive a $150 bonus each month you reach your sales quota. You reach your sales quota for each of 3 months. What is

the total amount you receive in bonuses for the three months? $50 $300 $350 $450 $600
Mathematics
1 answer:
Lera25 [3.4K]3 years ago
7 0

450

I used my head lol

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Which pairs of expressions are equivalent? more than one answer
Vilka [71]

Answer:

Correct answers are

First one

Second one

Third one

Step-by-step explanation:

3x+5x=8x

3(x+4)=3x+12

a+a+b=2a+b

4 0
3 years ago
Read 2 more answers
Given the data shown below, which of the following is the best prediction for
Soloha48 [4]

Answer:

The best prediction for  the number of years it will take for the population to reach 200,000 is 9.41

Step-by-step explanation:

Year     Population

1              11,920

2              16,800

3              23,300

4              33,000

5             45,750

6             64,000

y_1 =A _0 e ^{kt _1}\\y_2 = A_0 e^{k t_2}\\(t_1,y_1)=(1,11920)\\(t_2,y_2)=(2,16800)

Substitute the values

11920=A _0 e ^{k}  ---1\\16800 = A_0 e^{2k} ---2

Divide 1 and 2

\frac{11920}{16800}=\frac{e^k}{e^{2k}}\\\frac{11920}{16800}=e^{k-2k}\\ln(\frac{11920}{16800})=-k\\k=-1 ln(\frac{11920}{16800})\\k=0.3432\\A_0=y_1 e^{-k t_1}\\A_0=11920 e^{-0.3432}\\A_0=8457.5238

The exponential function that passes through the points (1, 11920) and (2, 16800) isy=8457.5238 e^{0.3432t}

Now we are supposed to find  the best prediction for  the number of years it will take for the population to reach 200,000

200000=8457.5238 e^{0.3432t}

\frac{200000}{8457.5238}=e^{0.3432t}

ln(\frac{200000}{8457.5238})=0.3432t

t = 9.41

Hence the best prediction for  the number of years it will take for the population to reach 200,000 is 9.41

6 0
4 years ago
For every 10,000 gallons of pool water, there needs to be 1 gallon of liquid chlorine. Steve has a 55,000 gallon pool. How much
Rudik [331]

Answer:

5.5 Gallons

Step-by-step explanation:

6 0
3 years ago
Please please help me on this.
quester [9]

Answer:

A

Step-by-step explanation:

An equation in the form y=kx represents something increasing at a constant <u>rate</u>

5 0
3 years ago
Two airplanes leave an airport at the same time, the first headed due north and the second at a bearing of N42^ E . At 2:00PM, t
Leno4ka [110]

Answer:

The two airplanes are about 330miles apart.

Step-by-step explanation:

The diagram interpreting the question has been attached to this response.

As shown in the diagram,

i. the airplanes leave at point C.

ii. at 2.00pm the first and second airplanes are at points A and B respectively, where they are 312miles and 487miles away from the starting point C in directions due north and N42E from the point C.

iii. the points A, B and C form a triangle with sides a, b and c.

To solve for the value of c which is the distance between the two planes at 2.00pm, the cosine rule is used.

c² = a² + b² - 2abcosC            --------------(i)

where;

b  = 312miles

a = 487miles

C = 42°

Substitute these values into equation (i) and solve as follows;

c² = (487)² + (312)² - 2(312)(487)cos(42)

c² = (237169) + (97344) - 303888cos(42)

c² = (237169) + (97344) - 303888(0.7431)

c² = 334513 - 225819.1728

c² = 108693.8272

<em>Take the square root of both sides</em>

√c² = √108693.8272

c = 329.69

c ≅ 330miles

Therefore, the two airplanes are far apart by 330miles

3 0
3 years ago
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