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Archy [21]
3 years ago
15

A stone is thrown upward from ground level. With what minimum speed should the stone be thrown so as to reach a height of 49 fee

t?
Mathematics
1 answer:
Sveta_85 [38]3 years ago
6 0
The correct answer of the given question above would be 8ft/sec. The minimum speed that the stone be thrown so as to reach a height of 49 feet is 8ft/sec. Consider this given solution here:
u^2 = 2x a x 1 
<span>u^2 = 2 x 32 x 1 </span>
<span>u = 8 ft/sec
</span>Hope this answer helps and this is what you are looking for.
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Due to a manufacturing error, two cans of regular soda were accidentally filled with diet soda and placed into a 18-pack. Suppos
crimeas [40]

Answer:

a) There is a 1.21% probability that both contain diet soda.

b) There is a 79.21% probability that both contain diet soda.

c)  P(X = 2) is unusual, P(X = 0) is not unusual

d) There is a 19.58% probability that exactly one is diet and exactly one is regular.

Step-by-step explanation:

There are only two possible outcomes. Either the can has diet soda, or it hasn't. So we use the binomial probability distribution.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

In which C_{n,x} is the number of different combinatios of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And \pi is the probability of X happening.

A number of sucesses x is considered unusually low if P(X \leq x) \leq 0.05 and unusually high if P(X \geq x) \geq 0.05

In this problem, we have that:

Two cans are randomly chosen, so n = 2

Two out of 18 cans are filled with diet coke, so \pi = \frac{2}{18} = 0.11

a) Determine the probability that both contain diet soda. P(both diet soda)

That is P(X = 2).

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

P(X = 2) = C_{2,2}(0.11)^{2}(0.89)^{0} = 0.0121

There is a 1.21% probability that both contain diet soda.

b)Determine the probability that both contain regular soda. P(both regular)

That is P(X = 0).

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

P(X = 0) = C_{2,0}(0.11)^{0}(0.89)^{2} = 0.7921

There is a 79.21% probability that both contain diet soda.

c) Would this be unusual?

We have that P(X = 2) is unusual, since P(X \geq 2) = P(X = 2) = 0.0121 \leq 0.05

For P(X = 0), it is not unusually high nor unusually low.

d) Determine the probability that exactly one is diet and exactly one is regular. P(one diet and one regular)

That is P(X = 1).

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

P(X = 1) = C_{2,1}(0.11)^{1}(0.89)^{1} = 0.1958

There is a 19.58% probability that exactly one is diet and exactly one is regular.

8 0
3 years ago
15 ) 2,145 please help I cant understand it​
Alika [10]
Sorry but there are no photos or anything, please post a photo or something so I can answer your question!
8 0
3 years ago
What is the midpoint of coordinates (6, 1) and (9, -3)?
ZanzabumX [31]

Answer:

(7.5, -1)

Step-by-step explanation:

hope this helps you!

4 0
2 years ago
If you horizontally compress the exponential function f(x) = 2x by a factor of 3, which of these is the equation of the new func
Blababa [14]
Your answer would be A.
4 0
2 years ago
Read 2 more answers
A bowl contains 3 red, 8 blue, and 7 black beads. Margaret randomly selects 3 beads one after the other without replacement. Fin
castortr0y [4]
Since your second pick is affected by your first pick & your third pick is affected by the first two, it is dependent. 

First pick: 18 marbles, 3 are red, so odds are 3/18 = 1/6 

Second pick: 17 marbles, 8 are blue, odds are 8/17 

Third pick: 16 marbles, 7 are black, odds are 7/16 

<span>1/6 * 8/17 * 7/16 = 56/1632 = 7/204 & as mentioned before it's dependent</span>
3 0
3 years ago
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