Answer:
y = 1/2x + 1
In order to evaluate a slope that is perpendicular to the given equation, you need to find the opposite reciprocal of the original slope. This means you take the original slope, flip the numerator and the denominator, and change the sign in front.
-2 ⇒ 1/2
Next, we need to substitute the information given into the point-slope formula.
The point-slope formula is:
y - y₁ = m(x - x₁)
y - 1 = 1/2(x - 0)
y - 1 = 1/2x
y = 1/2x + 1
Therefore, the line perpendicular to y = -2x + 2 is y = 1/2x + 1.
<span>f(x)=5x+3/6x+7
This means that f(6/x) = [</span>5(6/x)+3] / [6(6/x)+7] = [ 30/x +3 ] / [36/x +7]
If we assume x≠0 , f(6/x) = [30 +3x]/ [36 + 7x]
g(x)=√<span> [ x^2-4x ]
</span>
g(x-4) = √ [ (x-4)^2-4(x-4) ] = √ [ x² -8x +16 -4x +16 ] = √ [ x^2-12x +32]
10x + 2y = -2
2y = -10x -2
y = -5x - 1 (slope is -5 and a parallel line will have the same slope)
y = mx + b
slope(m) = -5
12 = -5(0) + b
12 = 0 + b
12 = b
so the parallel line is y = -5x + 12
hope this helps, God bless!
(3,-8)
You move down from those coordinates
X stays the same while it just moves down only Y changes