Question

Select the correct answer from the drop-down menu.

Answer 1

Missing term = –2xy

Solution:

Let us first find the quotient of $-8x^2y^3 \div xy$.

$-8x^2y^3 \div xy=\frac{-8x^2y^3 }{xy}$

                    $=\frac{-8\times x\times x\times y\times y\times y}{xy}$

Taking common term xy outside in the numerator.

                    $=\frac{xy(-8\times x\times y\times y)}{xy}$

Both xy in the numerator and denominator are cancelled.

                    $=-8xy^2$

Thus, the quotient of $-8x^2y^3 \div xy$ is $-8xy^2$.

Given the quotient of $-8x^2y^3 \div xy$ is same as the product  of 4xy and ____.

$-8xy^2=4xy$ × missing term

Divide both sides by 4xy, we get

⇒ missing term = $\frac{-8xy^2}{4xy}$

Cancel the common terms in both numerator and denominator.

⇒ missing term = –2xy

Hence the missing term of the product is –2xy.