Help me goddammit!!!! Solve the system of equations.

1 answer:

7 0

It should be -2,4 or -5,1.

since both answers = y then you put them equal to each other and then solved for x.

x+6=x^2 +8x +16
0=x^2 +7x +10
0=(x+2)(x+5)

x=-2 or -5

and for y I input the two separately into one of the equations

y= (-2)+6

y=4

y=(-5)+6

y=1

and then I double checked by imputing my y's and x's into the remaining equation.

(4)=(-2)^2 +8(-2)+16
4=4-16+16
4=4

(1)=(-5)^2 +8(-5)+16
1=25-40+16
1=1

I hope your tests go well with the help of this knowledge.

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belka [17]

Answer:

$\therefore 2\dfrac{1}{3} \div \left ( -3\dfrac{2}{3} \right ) = -\dfrac{7}{11}$

Step-by-step explanation:

The question relates to dividing a fraction by proper and another fraction

The given expression is presented as follows;

$2\dfrac{1}{3} \div \left ( -3\dfrac{2}{3} \right )$

We rearrange the fractions as improper fractions for easier division as follows;

$2\dfrac{1}{3} = \dfrac{7}{3}$

$-3\dfrac{2}{3} = -\dfrac{11}{3}$

Therefore, we have;

$2\dfrac{1}{3} \div \left ( -3\dfrac{2}{3} \right ) = \dfrac{7}{3} \div \left (-\dfrac{11}{3} \right ) = \dfrac{7}{3} \times \left (\dfrac{1}{-\dfrac{11}{3} } \right ) = \dfrac{7}{3} \div \left (-\dfrac{3}{11} \right ) =-\dfrac{7}{11}$