Help me goddammit!!!! Solve the system of equations.

1 answer:

7 0

It should be -2,4 or -5,1.

since both answers = y then you put them equal to each other and then solved for x.

x+6=x^2 +8x +16
0=x^2 +7x +10
0=(x+2)(x+5)

x=-2 or -5

and for y I input the two separately into one of the equations

y= (-2)+6

y=4

y=(-5)+6

y=1

and then I double checked by imputing my y's and x's into the remaining equation.

(4)=(-2)^2 +8(-2)+16
4=4-16+16
4=4

(1)=(-5)^2 +8(-5)+16
1=25-40+16
1=1

I hope your tests go well with the help of this knowledge.

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Someone help me please:)

IRISSAK [1]

Im not that good with these types of problems but i think it is b if my math is correct.

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3 years ago

VERY URGENT HAVE A TEST TO TAKE

Daniel [21]

The easiest way is to try the point (-4,1), that is, x=-4, y=1,
to see which equation works.
b works.

The usual way to do it is to find the equation of the circle
standard form of a circle is (x-h)²+(y-k)²=r², (h,k) are the coordinates of the center, r is the radius.
in this case, the center is (-2,1), so (x+2)²+(y-1)²=r²
the given point (-4,1) is for you to find r: (-4+2)²+(1-1)²=r², r=2
so the equation is (x+2)²+(y-1)²=2²
expand it: x²+4x+4+y²-2y+1=4
x²+y²+4x-2y+1=0, which is answer b.

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3 years ago

Coordinates will be fine PLs ASAP cause I need this rn<br> 13 POINTS!!!

grigory [225]

If the vertices of the triangle are J(-3,-5), K(-2,2) and L(1,-4) then its reflection in y axis are J(3,-5), K(2,2) and L(-1,-4)

Given,

The vertices of the triangle = J(-3,-5), K(-2,2) and L(1,-4)

We know,

In reflection in y axis (x,y) will become (-x,y)

Then the vertices of the reflection in y axis = J(3,-5), K(2,2) and L(-1,-4)

Draw the triangle using the vertices.

Hence, if the vertices of the triangle are J(-3,-5), K(-2,2) and L(1,-4) then its reflection in y axis are J(3,-5), K(2,2) and L(-1,-4)

Learn more about reflection here

brainly.com/question/15487308

#SPJ1

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2 years ago