Question

Please answer or I'll kill myse-I need to finish this asap.

Answer 1

2.

   a. y=6x+3

   b. 4x^2=(1/2)^x+1

   c. |9-2x|=3

3.

   a. i dont know how to answer this part

   b. if you plug it into the system 19.8 does not equal 40 and 31.1 doesn't equal 38

Answer 2

Answer:

a) Unique b) not a solution

Step-by-step explanation:

Given is a set of equations

$12x+3y=40\\7x-4y=38$

The system will have a unique solution if determinant formed by coefficients is not 0.

i.e. $\left[\begin{array}{ccc}12&3\\7&-4\\\end{array}\right] \\=-48+21\\=-27$

Since this value is not zero the system has a unique solution

b) To find whether a point is a solution, we can substitute that point and see. If the point satisfies both the equations, then it is a solution otherwise not.

$12(2.5)+3(-3.4)\\=30-10.2\\=19.8$

Since right side not equals 40, the point does not satisfy even the I equaiton.

Hence not a solution