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gulaghasi [49]
4 years ago
10

Find the critical points of the given function and then determine whether they are local maxima, local minima, or saddle points.

f(x, y) = cos(x2 + y2) consider only the three critical points (0, 0), π 2 , π 2 , and (0, π )

Mathematics
1 answer:
Liono4ka [1.6K]4 years ago
7 0

Answer:

Step-by-step explanation:

Check attachment for solution

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Derek owns a landscape business. He charges a fixed fee of $30 plus $1 per 1,000 square feet of lawn mowed. Derek's earnings (in
luda_lava [24]

From the given problem statement alone, we can say that the equation relating the area of the lawn mowed and the earnings has a linear relationship. That is because there is a constant increase in the earnings per area which is $1 per 1000 square feet.

Therefore the equation must be in the form of:

y = m x + b

where,

y = is the total earnings

m = is the fee per area = 1 / 1000

x = is the area of the lawn

b = is the fixed fee = 30

 

Therefore the equation becomes:

y = 0.001 x + 30

 

Rewriting this in terms for x since we are to find the area:

x = (y – 30) 1000

 

when y = 204

x = (204 – 30) 1000 = 174,000 square feet

 

when y = 344

x = (344 – 30) 1000 = 314,000 square feet

 

when y = 450

x = (450 – 30) 1000 = 420,000 square feet

 

when y = 482

x = (482 – 30) 1000 = 452,000 square feet

 

when y = 504

x = (504 – 30) 1000 = 474,000 square feet

8 0
3 years ago
What is the slope of the line that passes through the points (-1, 2) and (-4, 3)?
oksian1 [2.3K]

Answer:-1/3

Step-by-step explanation:

3 0
3 years ago
Derive the equation of the parabola with a focus at (-2,4) and a directrix of y=6 . Put the equation in standard form
Maru [420]

Answer:

y =  -  \frac{1}{4}  {(x + 2)}^{2}  + 5

Step-by-step explanation:

The vertex of this parabola is the midpoint of the focus (-2,4) and where the directrix intersects the axis of symmetry of the parabola (-2,6)

This parabola must open downwards due to the position of the directrix and has equation of the form:

{(x - h)}^{2}  =  - 4p(y - k)

where (h,k) is the vertex.

This implies that:

h =  - 2

and

k =  \frac{4 + 6}{2}  = 5

The value of p is the distance from the vertex to the focus:

p =  |6 - 5|  = 1

We substitute all the values into the formula to get:

(x -  - 2)^{2}  =  - 4(1){(y  - 5)}

{(x  + 2)}^{2}  =  - 4(y - 5)

Or

y =  -  \frac{1}{4}  {(x - 5)}^{2}  + 5

4 0
3 years ago
Which is bigger <br> 40% of 90 or<br> 1/2 of 80?
navik [9.2K]
40\%\cdot90=0.4\cdot90=36\\&#10;\dfrac{1}{2}\cdot80=40\\\\&#10;40>36\\&#10;\Downarrow\\&#10;\boxed{\dfrac{1}{2}\cdot80>40\%\cdot90}
8 0
3 years ago
Read 2 more answers
Can someone help me with this?
Grace [21]
R: -4,-3
S: -3,1
T: 1,-2
U: stays the same
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