All categories

3 years ago

What are the slope and the y-intercept of the linear function that is represented by the equation 8x - 2y = 5?

Mathematics

2 answers:

Karo-lina-s [1.5K]3 years ago

7 0

Answer:

the answer is C

Step-by-step explanation:

ivann1987 [24]3 years ago

6 0

Y=mx+b is the formula you need to get it in
start with the equation 8x-2y=5
so we want to get y by itself and everything else on the right side of the equation. to do this first subtract -8x from the left side and put it on the right side. this step would look like this:
8x-2y=5
-8x-2y=5 -> -2y=5-8x
-------------

next take and divide -2 from both sides of the equation. this would look like this:
-2y= 5 -8x
÷-2y=÷-2÷-2 -> y= -5/2 +4x
-------------------
so your new equation is y=4x-5/2 y=mx+b tells you the slope and y-intercept. m=slope and b=y-intercept. so in this case 4 is your slope and -5/2 is your y-int

You might be interested in

I WILL GIVE BRAINLIEST!!!! PLZ HELPS ASAP!!!

Phantasy [73]

Answer:

x = xi + delta x

-2+1 = -1

y = yi + delta y

-5+3 = -2

(-1,-2)

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

The base of a pyramid is a square with side lengths of 5 centimeters. The slant height of each lateral face of the pyramid is 6

Lena [83]

Answer:

85 cm²

Step-by-step explanation:

The base is a square with side length 5 cm. The area of this base is

A = s² = (5 cm)² = 25 cm².

If the slant height of each lateral face of the pyramid is 6 cm, then we can find the area of each such face using the area-of-a-triangle formula,

A = (1/2)(base)(height), which here is

A = (1/2)(5 cm)(6 cm) = 15 cm² per lateral side.

The total area of these sides is 4(15 cm²) = 60 cm².

Then the total surface area of the pyramid is A = 60 cm² + 25 cm² = 85 cm².

4 0

4 years ago

-6x + 7y = 9<br> 2x - 2y = 4<br> Solve for x and y

Effectus [21]

Answer:

x = 23 , y = 21

Step-by-step explanation:

-6x + 7y = 9 -- (1)

2x - 2y = 4 -- (2)

(2) x 3 : 6x - 6y = 12 -- (2)'

(1) + (2)' : y = 21 -- (3)

Subtituting (3) into (2),

2x - 42 = 4

2x = 46

x = 23 -- (4)

According (3) and (4),

x = 23 , y = 21

If this helps you, please give brainliest!

7 0

3 years ago

One year Thomas had the lowest ERA (earned-run average, mean number of runs yielded per nine inning pitched) of any male pitcher

valkas [14]

Answer:

Thomas had an ERA with a z-score of -2.82.

Karla had an ERA with a z-score of -2.81.

Thomas had the better year compared with his peers, since his ERA had the lower Zscore.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by

$Z = \frac{X - \mu}{\sigma}$

The ERA is the Earned Runs Average per 9 innings. This mean that the lower the ERA is, the better it is. So, between Thomas and Karla, whoever has the lower Zscore had the better season.

Thomas

For the males, the mean ERA was 4.837 and the standard deviation was 0.541. This means that $\mu = 4.837, \sigma = 0.541$ .

Thomas ERA was 3.31. This means that $X = 3.31$

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{3.31 - 4.837}{0.541}$

$Z = -2.82$

Thomas had an ERA with a z-score of -2.82.

Karla

For Females, the mean ERA was 4.533 and the standard deviation was 0.539. This means that $\mu = 4.533, \sigma = 0.539$ .

Karla ERA was 3.02. So $X = 3.02$ .

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{3.02 - 4.533}{0.539}$

$Z = -2.81$

Karla had an ERA with a z-score of -2.81

Which player had a better year in comparison with their peers?

Thomas had the better year compared with his peers, since his ERA had the lower Zscore.

6 0

3 years ago

Two forces with magnitudes of 150 and 100 pounds act on an object at angles of 30° and 120°, respectively. Find the direction an

lyudmila [28]

<h2>Answer:</h2>

$Magnitude=180.27 \ lbf \\ \\ Direction=63.69 \ degrees$

<h2>Step-by-step explanation:</h2>

We have two forces as follows:

<u>First force:</u>

Magnitude: 150 pounds

Angle: 30°

<u>First force:</u>

Magnitude: 100 pounds

Angle: 120°

So the components can be found as follows:

$F_{1x}=150cos(30)=129.90 \ lbf\\F_{1y}=150sin(30) = 75 \ lbf \\ \\ F_{2x}=100cos(120)=-50 \ lbf\\F_{2y}=100sin(120) = 86.60 \ lbf$

So the components of the resultant force can be found by adding each component of the individual forces as follows:

$R_{x}=\Sigma F_{x} \\ R_{y}=\Sigma F_{y} \\ \\ R_{x}=129.90-50=79.90 \ lbf \\ R_{y}=75+86.60=161.6 \ lbf$

Finally, the magnitude and direction of the resultant force is:

$Magnitude \rightarrow R=\sqrt{R_{x}^2+R_{y}^2}=\sqrt{79.90^2+161.6^2}=180.27 \ lbf \\ \\ Direction \rightarrow \theta=tan^{-1}(\frac{R_{y}}{R_{x}})=tan^{-1}(\frac{161.6}{79.90})=63.69 \ degrees$

6 0

3 years ago

Read 2 more answers