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2 years ago

A tree was 8 feet tall when it was planted. After 5 years, it was 18 feet tall. What was the tree’s growth rate?

Mathematics

2 answers:

nata0808 [166]2 years ago

8 0

y=2x+8

it is 2 feet per each year

Elena L [17]2 years ago

6 0

It grew 2 ft per year because you take 8 ft away from the 18 then divide that now 10 by 5 to get 2 ft per year

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Here try to figure out this problem

Marysya12 [62]

Answer:

Step-by-step explanation:

2 is the slope, it's going up 2, and right 1 which is 2/1 or just 2

Hope this helps

7 0

2 years ago

Write out the first four terms of the series to show how the series starts. Then find the sum of the series or show that it dive

Nostrana [21]

Answer:

The first four terms of the series are

$(9+3),(\frac97+\frac35),(\frac9{7^2}+\frac3{5^2}),(\frac9{7^3}+\frac3{5^3})$

$\sum_{n=0}^\infty \frac9{7^n}+\frac{3}{5^n}$ = 14.25

Step-by-step explanation:

We know that

Sum of convergent series is also a convergent series.

We know that,

$\sum_{k=0}^\infty a(r)^k$

If the common ratio of a sequence |r| <1 then it is a convergent series.

The sum of the series is $\sum_{k=0}^\infty a(r)^k=\frac{a}{1-r}$

Given series,

$\sum_{n=0}^\infty \frac9{7^n}+\frac{3}{5^n}$

$=(9+3)+(\frac97+\frac35)+(\frac9{7^2}+\frac3{5^2})+(\frac9{7^3}+\frac3{5^3})+.......$

The first four terms of the series are

$(9+3),(\frac97+\frac35),(\frac9{7^2}+\frac3{5^2}),(\frac9{7^3}+\frac3{5^3})$

Let

$S_n=\sum_{n=0}^\infty \frac{9}{7^n}$ and $t_n=\sum_{n=0}^\infty \frac{3}{5^n}$

Now for $S_n$ ,

$S_n=9+\frac97+\frac{9}{7^2}+\frac9{7^3}+.......$

$=\sum_{n=0}^\infty9(\frac 17)^n$

It is a geometric series.

The common ratio of $S_n$ is $\frac17$

The sum of the series

$S_n=\sum_{n=0}^\infty \frac{9}{7^n}$

$=\frac{9}{1-\frac17}$

$=\frac{9}{\frac67}$

$=\frac{9\times 7}{6}$

=10.5

Now for $t_n$

$t_n= 3+\frac35+\frac{3}{5^2}+\frac3{5^3}+.......$

$=\sum_{n=0}^\infty3(\frac 15)^n$

It is a geometric series.

The common ratio of $t_n$ is $\frac15$

The sum of the series

$t_n=\sum_{n=0}^\infty \frac{3}{5^n}$

$=\frac{3}{1-\frac15}$

$=\frac{3}{\frac45}$

$=\frac{3\times 5}{4}$

=3.75

The sum of the series is $\sum_{n=0}^\infty \frac9{7^n}+\frac{3}{5^n}$

= $S_n+t_n$

=10.5+3.75

=14.25

4 0

3 years ago

Plz help I have a geometry exam soon!!!!! :(

Pachacha [2.7K]

Answer:

a = 93°, b = 120°, c = 150°

Step-by-step explanation:

b + 36 = 78 × 2 => b + 36 = 156 => b = 120°

87 × 2 - b = the minor arc between a and 78

=> 174 - 120 = 54

54 + b + 36 + c = 360

=> 54 + 120 + 36 + c = 360

=> c = 150°

(c + 36) ÷ 2 = a

=> (150 + 36) ÷ 2 = a

=> a = 93°

5 0

2 years ago

Find the slope between the points: (3,4) and (-1,-2)

pshichka [43]

Answer:

3/2 hope this helps hqhahjajja

8 0

2 years ago

Which equation can be used to solve for x in the following diagram?<br> 7xº<br> 11x°

telo118 [61]

Answer:

7x° + 11x° = 90°

(Required equation)

Step-by-step explanation:

7x° + 11x° = 90°

(complementary angles)

18x° = 90°

18x = 90

x = 90/18

x = 5

8 0

3 years ago