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2 years ago

7

What is the value of each expression in the simplest form? -11/15 + (-2/15)

1 answer:

Liula [17]2 years ago

6 0

Answer:

$\frac{ - 13}{15}$

Step-by-step explanation:

$\frac{ - 11}{15} + \frac{ - 2}{15} = \frac{( - 11 - 2)}{15} = \frac{ - 13}{15}$

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use the plot of the concentration of cu(no3)3 versus absorbance provided. if the absorbance of an unknown was determined to be 0

Helen [10]

Using the linear regression equation, the concentration of the unknown solution is 0.2161 M.

Linear regression describes the relationship of two variables. It may not be exact but it is the line that best fit the data. The equation for a linear regression is in the form y = bx + a, where x and y are the two variables.

If the absorbance of an unknown was determined to be 0.67 absorbance units, using the linear regression equation provided from the plot, substitute the value of absorbance to the variable y and solve for the value of x or the concentration.

y = 3.8674x - 0.1657

0.67 = 3.8674x - 0.1657

3.8674x = 0.67 + 0.1657

3.8674x = 0.8357

x = 0.2161

Hence, the concentration is 0.2161 M.

Learn more about linear regression here: brainly.com/question/25311696

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1 year ago

Math Tutor Pay: $11.44 per hour

slavikrds [6]

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3 years ago

Read 2 more answers

Three scatterplots are shown, along with their best-fit lines and correlation coefficients, r1, r2, and r3. Choose the correct s

ira [324]

Answer:

C) r3 < r2 < r1

Step-by-step explanation:

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3 years ago

For his birthday, Tyrone's parents gave him $7,790.00 which they put into a savings account that earns 15% interest compounded m

torisob [31]

Answer:

5 years and 5 months

Step-by-step explanation:

<u />

<u>Compound Interest Formula</u>

$\large \text{$ \sf A=P(1+\frac{r}{n})^{nt} $}$

where:

A = final amount
P = principal amount
r = interest rate (in decimal form)
n = number of times interest applied per time period
t = number of time periods elapsed

Given:

A = $17,474.00
P = $7,790.00
r = 15% = 0.15
n = 12
t = number of years

Substitute the given values into the formula and solve for t:

$\implies \sf 17474=7790\left(1+\dfrac{0.15}{12}\right)^{12t}$

$\implies \sf \dfrac{17474}{7790}=\left(1.0125}\right)^{12t}$

$\implies \sf \ln\left(\dfrac{17474}{7790}\right)=\ln \left(1.0125}\right)^{12t}$

$\implies \sf \ln\left(\dfrac{17474}{7790}\right)=12t \ln \left(1.0125}\right)$

$\implies \sf t=\dfrac{\ln\left(\frac{17474}{7790}\right)}{12 \ln \left(1.0125}\right)}$

$\implies \sf t=5.419413037...\:years$

Therefore, the money was in the account for 5 years and 5 months (to the nearest month).

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1 year ago

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Which of the following functions best describes this graph?

natita [175]

The answer is A sorry if I’m wrong

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