At a schools field day, students will throw table tennis balls then measure the distance. There are 626 students in the school.
1 answer:
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Step-by-step explanation:
- 1
vector AB(3-(-6); 5-7)
vector AB(9;-2)
AB= =
- 2
M is the midpoint of AB
we have B(-5;10) and M(1;7)
let A(x;y)
(x-5)/2 = 1 ⇒ x-5 = 2⇒ x = 7
(10=y)/2 = 7⇒ 10+y = 14 ⇒y= 4
so : A(7;4)
- 3
the center of the circle is the midponit of the line joining both ends of the diameter
let A(x;y) be the other end
(-2+x)/2 = 2 ⇒ -2+x = 4⇒ x= 6
(5=y) = -1 ⇒ 5+y = -2 ⇒ y= -7
so the coordinates of the other end are (6; -7)
- 4
A,B and C are collinear such as AB=BC so b is the midpoint of AC
(-5+1)/2 = y ⇒ y = -4/2 ⇒ y = -2
((-3=x)/2 = 7 ⇒ -3+x = 14 ⇒ x = 17
so x= 17 and y = -2
Answer:
option C
A number line with a closed circle on and shading to the left
Step-by-step explanation:
we have
solve for x
Subtract both sides
Divide by both sides
--------> is equivalent to
The solution is the interval--------> [9,∞)
All real numbers greater than or equal to
A number line with a closed circle on and shading to the right
Answer:
The vertex of the function is at (1,-25)
Step-by-step explanation:
I think your question missed key information, allow me to add in and hope it will fit the orginal one.
<em>Part of the graph of the function f(x) = (x + 4)(x-6) is shown below. </em>
<em>Which statements about the function are true? Select two </em>
<em>options. </em>
<em>The vertex of the function is at (1,-25). </em>
<em>The vertex of the function is at (1,-24). </em>
<em>The graph is increasing only on the interval -4< x < 6. </em>
<em>The graph is positive only on one interval, where x <-4. </em>
<em>The graph is negative on the entire interval </em>
My answer:
Given the factored form of the function:
f(x) = (x + 4)(x-6)
<=> f(x) =
We will convert to vertex form
<=> f(x) = () - 25
<=> f(x) =
=> the vertex of the function is: (1,-25)
We choose: a. The vertex of the function is at (1,-25)
Let analyse other possible answers:
<u>c. The graph is increasing only on the interval -4< x < 6.</u>
Because the parameter a =1 so the graph open up all over its domain and the vertex is the lowest point.
So the graph is increasing in the domain (1, +∞)
=> C is wrong
<u>d. The graph is positive only on one interval, where x <-4</u>
Wrong, The graph is positive only on one interval, where x > 6
<u>e. The graph is negative on the entire interval</u>
Wrong, The graph is negative only on one interval, where -4< x < 6.
