All categories

2 years ago

Which equation could have been used to create this function table?

Mathematics

1 answer:

alina1380 [7]2 years ago

5 0

A) y=3x
You can plug in the given values (inputs) of x to see if it creates the number in y (output).
3*1=3
3*2=6
3*3=9
3*4=12
3*5=15
3*6=18

All these values are true, therefore the equation y=3x is the correct answer.

:)

You might be interested in

Select the equation of the line that passes through the .5,7 and is perpendicular to the line x equals 4

lions [1.4K]

Hello!

To be perpendicular to x = 4, the line must be y = something. This eliminates answer choices #2 and #4. Also, to pass through the point (.5, 7), the line must be y = 7.

So answer choice #3.

Hope this helps!! Let me know if you have ANY questions.

8 0

2 years ago

Which expression is equivalent to 73 ⋅ 7−5?

Alex787 [66]

Expression for 73•7-5?

Answer is 506

8 0

2 years ago

Read 2 more answers

If roberto can build 1 house in 23 days, how many houses can he build in 207 days?

rusak2 [61]

He would be able to build 9 houses.

$\frac{207}{23} = 9$

3 0

3 years ago

What is the solution to the system of equations represented by these two lines?

Andrei [34K]

Answer:

(3,2)

Step-by-step explanation:

this is an intersecting lines which means it has one solution

8 0

2 years ago

Please help me with this

Ne4ueva [31]

Answer:

Option c

Step-by-step explanation:

A system of equations are given to us. And we need to solve them . The given system is

$\begin{cases} y = 2x - 3\dots 1 \\ y = x^2 - 3\dots 2 \end{cases}$

We numbered the equations here . Now put the value of equation 1 in equation 2 that is substituting y = 2x - 3 in eq. 2 .

$\implies y = x^2 - 3 \\\\\implies 2x - 3 = x^2 - 3 \\\\\implies x^2 - 2x = 0 \\\\\implies x(x-2) = 0 \\\\\implies\red{ x = 0 , 2 }$

We got two values of x as 0 & 2 . Alternatively substituting these values we have ,

$\implies y = 2 x - 3 \\\\\implies y = 2(0)-3 \qquad or \qquad y = 2(2)-3 \\\\\implies y = 0-3 \qquad or \qquad 4 - 3 \\\\\implies \red{ y = -3 , 1 }$

Thefore the required answer is ,

$\red{Option\:c} \begin{cases} (0,-3) \\ (2,1) \end{cases}$

4 0

2 years ago

Read 2 more answers