Yes it is correct ur answer is well solved and good Alice will finish the race
Answer:
- (g/d, initial, factor, rate)
- (g, 45, 1.05, 5%)
- (d, 50, 0.70, -30%)
- (g, 90, 1.42, 42%)
- (d, 120, 0.45, -55%)
Step-by-step explanation:
Exponential functions all have the form ...
f(x) = (initial value)(growth factor)^x
where (growth factor) is defined as ...
(growth factor) = (1 + growth rate) ⇒ growth rate = growth factor - 1
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If the growth rate is negative (growth factor is less than 1), then it is decay, rather than growth. Growth rate is often expressed as a percentage. A growth rate of a negative amount may be reported as a decay rate of a positive amount. (Above, we have kept the decay rates negative to reinforce the fact that they are decay. <em>Your grader may expect these values to be positive</em>.)
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So, to fill in the table, compare the given functions to the form above. The results are listed in the answer section above.
Answer:For this case we have that by definition it is fulfilled:
Where:
a: It is the base
b: It is the exponent
So, if we have the following expression:
-6 to the power of 4, is equivalent to:
So we have to:
-6: It is the base
4: It is the exponent
-6: It is the base
4: It is the exponent
Step-by-step explanation:
Answer:
1:00 a.m. (and 3:00 a.m., and 5:00 a.m.)
Step-by-step explanation:
The problem is to find the least common multiple (LCM) of the barking intervals. One way to find the LCM is to find the product of the factors of the numbers.
... 5 = 5 . . . . a prime number
... 8 = 2³
... 12 = 2²×3
The factor 2³ is a multiple of the factor 2², so we only need 2³ in our final product.
The LCM is then ...
... 2³×3×5 = 120 . . . . minutes
The dogs will all bark together every 120 minutes (2 hours).
2 hours after 11 p.m. is 1 a.m.
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The problem statement doesn't say whether Ms. Li was awakened multiple times. The dogs will bark together again at 3 a.m., 5 a.m. and (possibly) 7 a.m.
