How do i find the area between the two curves

Mathematics

1 answer:

viktelen [127]4 years ago

4 0

A=22/10

A=integral(a,b) [f(x)-g(x)]dx

Since the function is even (the function is mirrored over the y axis) we can evaluate the integral from 0 to 1 and then multiply our answer by 2 since we have the same area on each side of the y axis.

We get A=2*int.(0, 1)[(x^2)-(-2x^4)]dx

Now we can integrate by term.

2*[int.(0, 1)[x^2]dx+int(0, 1)[2x^4]dx]

Now factor out constants.

2*[int(0,1)[x^2]dx+2int(0,1)[x^4]dx]

Now integrate.

2*[(x^3/3)|(0,1) + 2*(x^5/5)|(0,1)]

Now solve.

2*[(1/3)+2*(1/5)]

=22/10

Hope you can decipher what I wrote!

You might be interested in

Need some help. :/

Allushta [10]

I don’t have any graph paper but on 2x draw a line from the very right to the very left and shade the entire left side. And then on -3 draw a line from the very top to the very bottom and shade the top part. Unless you don’t shade it then don’t do that but that’s what you have to do

4 0

3 years ago

Examples of rational numbers

diamong [38]

Examples of rational numbers :
1, 1/2, 3/4 , 5 , 6, 15/8 etc

Rational numbers are numbers which can be written as fraction as also that the numerator and denominator are whole examples.
Example 5 can be written as fraction in the form of 5/1.

7 0

4 years ago

In a 30-60-90 triangle, the hypotenuse is the shorter leg times the square root of two.

Free_Kalibri [48]

False!

<span>In a 30-60-90 triangle, the hypotenuse (c) is twice the length of the shorter leg (a): c = 2a
</span>In a 30-60-90 triangle, the longer leg (b) is equal to the shorter leg (a) multiplied by √3: b = a√3

7 0

3 years ago

Help with math pls cant figure it out

tatyana61 [14]

Answer:

$\frac{5}{4}+or-\frac{3i\sqrt{7} }{4}$

Step-by-step explanation:

You can solve this equation with the quadratic formula which is:

$m_{1,2}=\frac{-b+or-\sqrt{b^{2}-4ac } }{2a}$

All you need to do is rearrange the equation (add $-\frac{11}{2}$ to both sides and then multiply both sides by 2) to get:

$2m^2-5m+11=0$

From this new equation, we can easily see that a = 2, b = -5, and c = 11 AND you don't have to work with as many fractions. Substitute the values for a, b, and c into the quadratic formula to get:

$m_{1,2}=\frac{5+or-\sqrt{(-5)^{2}-4(2)(11) } }{2(2)}$