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3 years ago

PLEASE HELP ANYONE WOULD HELP ME PASSS

Mathematics

1 answer:

Lana71 [14]3 years ago

4 0

1. 5/11
2. 11
3. 2

These are all just properties of logarithms.

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Use the equation and type the ordered-pairs. y = log 3 x {(1/3, a0), (1, a1), (3, a2), (9, a3), (27, a4), (81, a5)

vagabundo [1.1K]

Answer:

Considering the given equation $y = log_{3}x\\$

And the ordered pairs in the format $(x, y)$

I don't know if it is log of base 3 or 10, but I will assume it is 3.

For $(\frac{1}{3}, a_{0} )$

$x=\frac{1}{3}$

$y=a_{0}$

$y = log_{3}x\\y = log_{3}(\frac{1}{3} )\\y=-\log _3\left(3\right)\\y=-1$

So the ordered pair will be $(\frac{1}{3}, -1 )$

For $(1, a_{1} )$

$x=1$

$y=a_{1}$

$y = log_{3}x\\y = log_{3}1\\y = log_{3}(1)\\Note: \log _a(1)=0\\y = 0$

So the ordered pair will be $(1, 0 )$

For $(3, a_{2} )$

$x=3$

$y=a_{2}$

$y = log_{3}x\\y = log_{3}3\\y = 1$

So the ordered pair will be $(3, 1 )$

For $(9, a_{3} )$

$x=9$

$y=a_{3}$

$y = log_{3}x\\y = log_{3}9\\y=2\log _3\left(3\right)\\y=2$

So the ordered pair will be $(9, 2 )$

For $(27, a_{4} )$

$x=27$

$y=a_{4}$

$y = log_{3}x\\y = log_{3}27\\y=3\log _3\left(3\right)\\y=3$

So the ordered pair will be $(27, 3 )$

For $(81, a_{5} )$

$x=81$

$y=a_{5}$

$y = log_{3}x\\y = log_{3}81\\y=4\log _3\left(3\right)\\y=4$

So the ordered pair will be $(81, 4 )$

4 0

3 years ago

A road crew much repave a road that is 4/5 miles long. They can repave 1/20 miles each hour. How long will it take the crew to r

lutik1710 [3]

Answer:

16 hours

Step-by-step explanation:

Multiply the 4/5 by 4 to get the denominator as 20. So you do 4 x 4 which equals 16 and 5 x 4 which equals 20 so you get 16/20 miles or 16 hours.

3 0

2 years ago

Can someone show me how to do this?

andriy [413]

3/4 ( (-50+2)/5)
= 3/4 ( -48/5)
= 3/4 * -48/5
= -36/5

6 0

3 years ago

The circumference of a circle can be found using the

hichkok12 [17]

Answer:

It is the <em><u>second one</u></em>

Step-by-step explanation:

1st option does not include the number 2 from the equation above,

and 3 and 4, you do not have to divide anywhere in the equation, so those are no possibly correct.

6 0

3 years ago

Approximate the zeros of the function. Round to the nearest tenth if necessary. f(x) = 4x^2 + 4x - 35. Explain each step on how

svet-max [94.6K]

4x²+4x-35=0
factor: (2x+7)(2x-5)=0
2x+7=0, or 2x-5=0
2x=-7 or 2x=5
x=-3.5 or x=2.5

I don't see any rounding necessary in this case.

when you factor ax²+bx+c, you take the two factors of a and the two factors of c, one factor of a times one factor of c, the other factor of a times the other factors, the sum of the two products make b.
in this case, the factors of 4 is 2 and 2, the factors of -35 is -5 and 7. I line them up in the following way:
2 -5

2 7
then I multiple them diagonally, the top left 2 multiplying the bottom right 7=14, and the other 2 multiplying -5=-10, 14 and -10 make a sum of 4.

if you don't get the desired sum, switch the factors up and down till you have the right combination. Note: Do not switch left and right.

I hope this makes sense to you.

8 0

3 years ago