<u>Complete Question:</u>
Janeel has a 10 inch by 12 inch photograph. She wants to scan the photograph, then reduce the results by the same amount in each dimension to post on her Web site. Janeel wants the area of the image to be one eight of the original photograph. Write an equation to represent the area of the reduced image. Find the dimensions of the reduced image.
<u>Correct Answer:</u>
A) 
B) Dimensions are : Length = 10-x = 3 inch , Breadth = 12-x = 5 inch
<u>Step-by-step explanation:</u>
a. Write an equation to represent the area of the reduced image.
Let the reduced dimensions is by x , So the new dimensions are

According to question , Area of new image is :
⇒ 
⇒ 
⇒ 
So the equation will be :
⇒ 
b. Find the dimensions of the reduced image
Let's solve : 
⇒ 
⇒ 
⇒ 
By Quadratic formula :
⇒ 
⇒ 
⇒ 
⇒
x = 15 is rejected ! as 15 > 10 ! Side can't be negative
⇒ 
Therefore, Dimensions are : Length = 10-x = 3 inch , Breadth = 12-x = 5 inch
Answer:
Option 2
Step-by-step explanation:
Minimum value is going to be in the y part of our coordinate, so we can just look there. I went ahead and used a graphing calculator to make things easy.
Starting off with option 2, we can see the minimum is -10. And in option 4 we can see the smallest y value is -6.
Using a graphing calculator (I used desmos), we can graph these other functions and figure out their minimums.
Option 1's y minimum is -7, and Option 3's y minimum is -2.25.
Option 1: -7
Option 2: -10
Option 3: -2.25
Option 4: -6
The questions asks for the <em>smallest</em> minimum value, which in this case is option 2.
The answer to this question is A