Answer:
Domain and range » Tips for entering queries. Enter your queries using plain English. To avoid ambiguous queries, make sure to use parentheses where necessary. Here are some examples illustrating how to ask for the domain and range. domain of log(x) (x^2+1)/(x^2-1) domain; find the domain of 1/(e^(1/x)-1) function domain: square root of cos(x)
Step-by-step explanation:
Answer:
The midpoint is (8,9.5)
Step-by-step explanation:
The midpoint is found by averaging the x coordinates and the y coordinates
x = (x1+x2)/2 y = (y1+y2)/2
x = (13+3)/2 = 16/2 = 8
y = (5+14)/2 = 19/2 = 9.5
The midpoint is (8,9.5)
Answer:
the answer is 94cm
Step-by-step explanation:
1m=100cm
0.94m= 0.94×100
= 94cm
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<em>Hope</em><em> </em><em>it</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>you</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em></h2>
Answer:
c=sqrt(b^2+9), -sqrt(b^2+9)
Step-by-step explanation:
c^2-9=b^2
c^2=b^2+9
c=sqrt(b^2+9), -sqrt(b^2+9)
