<span>Vector Ā * Vector B = -10. This is the scalar dot product and can calculated by taking the magnitude in the x, y, and z of the two vectors and the operation is done.
The angle </span> Ɵ AB between vector Ā and vector B is 133.635°.
<span>2 Vector B * 3 Vector C = -1. A similar approach is done for this one.</span>
<h3>
Answer: ASA</h3>
Explanation:
The arc markings for each angle show that we have two pairs of congruent angles (angle O = angle Q, angle M = angle R). This takes care of the two "A"s in "ASA". The tickmarks show us that the sides MO and RQ are the same length, so this takes care of the "S" of "ASA". Note the congruent sides are between the angles mentioned. The order is important.
First, find the area of each figure. Then subtract the smaller area from the larger area. Your work should look something like this:
A = l * w
A = 9 * 9
A = 81
This is the area of the smaller square. Now find the area of the larger square.
A = l * w
A = 15 * 15
A = 225
Now subtract the two areas to find the area of the shape that is left when the smaller square is cut out.
225 - 81 = 144
Your final answer should be:
144 in^2
Answer:
y = 6/5x - 2
Step-by-step explanation:
slope is 6/5 with point (5, 4)
y = mx + b
4 = 6/5(5) + b
4 = 30/5 + b
4 = 6 + b
-6 -6
--------------------
-2 = b
So, y = 6/5x - 2 is the equation.
The formula for the volume of a cube is:
V = a^3
Plug in what we know:
125 = a^3
Cube the other side:
![a = \sqrt[3]{125}](https://tex.z-dn.net/?f=a%20%3D%20%5Csqrt%5B3%5D%7B125%7D%20)
