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elena55 [62]
3 years ago
7

Triangle HIJ has been reflected to create triangle H'I'J'. Segment HJ= H'J'= 4, segments IJ = I'J' = 7, and angles J and J' are

both 32 degrees. Which postulate below would prove the two triangles are congruent?. Select one:. a. SSS. b. SAS. c. ASA. d. AAS
Mathematics
2 answers:
svlad2 [7]3 years ago
8 0
The postulate that prove that the two triangles in your problem is congruent is SAS or Side Angle Side postulate. This postulate is use when the given of an equation are only 2 side and an angle and also it gives the answer or the side on which the angle is projected. By means of that you can tell or figure out that the two triangle is congruent. So the answer is letter B. SAS
jekas [21]3 years ago
8 0

<span>The postulate that would prove that the two triangles are congruent is SAS. </span><span>The correct answer between all the choices given is the second choice or letter B. I am hoping that this answer has satisfied your query about this specific question.</span>

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Given:

Compound shape

To find:

The area of the compound shape.

Solution:

The compound shape is splitted into two parallelograms.

<u>Bottom parallelogram:</u>

Base = 7.5 cm

Height = 5 cm

Area of the parallelogram = base × height

                                           = 7.5 × 5

                                           = 37.5 cm²

The area of the Bottom parallelogram 37.5 cm².

<u>Top parallelogram:</u>

Base = 7.5 cm

Height = 4.5 cm

Area of the parallelogram = base × height

                                           = 7.5 × 4.5

                                           = 33.75 cm²

The area of the top parallelogram 33.75 cm².

Compound shape = 37.5 + 33.75

                               = 71.25 cm²

The area of the compound shape is 71.25 cm².

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Answer:

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Step-by-step explanation:

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If d , e, and f are midpoints of the sides of ABC, find the perimeter of ABC.
ehidna [41]

Answer:

Perimeter of the ΔDEF = 10.6 cm

Step-by-step explanation:

The given question is incomplete; here is the complete question with attachment enclosed with the answer.

D, E, and F are the midpoints of the sides AB, BC, and CA respectively. If AB = 8 cm, BC = 7.2 cm and AC = 6 cm, then find the perimeter of ΔDEF.

By the midpoint theorem of the triangle,

Since D, E, F are the midpoints of the sides AB, BC and CA respectively.

Therefore, DF ║ BC and FD=\frac{1}{2}\times(BC)

FD = \frac{7.2}{2}

     = 3.6

Similarly, FE=\frac{1}{2}\times(AB)

FE=\frac{8}{2}

FE = 4 cm

And DE=\frac{AC}{2}

DE = \frac{6}{2}

     = 3 cm

Now perimeter of ΔDEF = DE + EF + FD

= 3 + 4+ 3.6

= 10.6 cm

Perimeter of the ΔDEF is 10.6 cm.

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