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Margaret [11]
3 years ago
15

2.

ddle" class="latex-formula">
find each square root​
Mathematics
2 answers:
LuckyWell [14K]3 years ago
6 0

Answer:

√3x3

The answer is 3......

stealth61 [152]3 years ago
3 0
The square root of this is 3. 3x3=9
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2. Solve the following system of equations
notsponge [240]

Answer:

The answer to your question is x = 2, y = -1, z = 3

Step-by-step explanation:

Data

          x  +  y  +  z =  4

          x  - 2y  -  z =   1

         2x  -  y  - 2z = -1

Solve the system of equations

          |  1   1   1  |

          |   1 -2 - 1 |

Δ =     |  2  -1  -2|    = (4 - 1 -2) - (-2 + 1 -4) = 1 + 5 = 6

          |  1    1   1  |

          |  1  -2  -1 |  

         | 4   1   1 |

         | 1   -2  -1 |

Δx =   |-1   -1   -2|   = (16 - 1 + 1) - (-2 + 4 + 2) = 16 + 4 = 12

         | 4   1    1 |

         |  1  -2  -1 |

         | 1   4   1  |

         | 1    1  -1  |

Δy =  | 2 - 1  -2 | = (-2 -1 -8) - (-8 + 1 + 2) = -11 - 5 = -6

         | 1   4    1 |

         | 1    1    -1|

         | 1   1   4|

         | 1 -2   1|

Δz =  | 2 -1   -1|   = (2 - 4 + 2) - (-1 -1 -16) = 0 + 18

         | 1   1    4|

         | 1  -2   1|

Find x, y and z

x = Δx/ Δ = 12/6 = 2

y = Δy/Δ = -6/6 = -1

z = Δz/Δ = 18/6 = 3

6 0
3 years ago
Is the expression 3 (x+ 1 1\2) -3 equivalent to 3x + 1 1\2
Olenka [21]

Answer:

Yes

Step-by-step explanation:

3 ( x + 1.5 ) - 3

Distribute out the 3 to ( x + 1.5 )

3x + 4.5 - 3

3x + 1.5

8 0
3 years ago
Read 2 more answers
Dakota knows that EJ←→⊥CN←→ and CN←→∥KT←→ .
Lina20 [59]

Answer:

  • m∠CJV=90°
  • EV←→⊥KT←→

Step-by-step explanation:

Nothing in the problem statement tells you anything about the directions of lines LK or QT, so you cannot conclude they are parallel. You only know that EV crosses CN and KT at right angles.

EJ ⊥ CN means m∠CJV = 90°, as all angles at the intersection of EJ and CN are 90°.

6 0
3 years ago
Rewrite the following without an exponent. 6^-2<br> Please answer ASAP!
julia-pushkina [17]

Answer:

Rewriting 6^{-2} without an exponent we get \mathbf{\frac{1}{36}}

Step-by-step explanation:

We need to rewrite the following without an exponent. 6^{-2}

We need to solve the exponent to find the result.

We know the exponent rule: a^{-b}=\frac{1}{a^b}

Now using this rule to solve the equation:

6^{-2}\\=\frac{1}{6^2}\\We \:know \:that\:6^2 = 6\times 6=36\\=\frac{1}{36}

So, Rewriting 6^{-2} without an exponent we get \mathbf{\frac{1}{36}}

8 0
3 years ago
What is the y-intercept of the line passing through the point (9-7) and has a slope of -1/8
Lina20 [59]
Y - y1 = m(x - x1)
y + 7 = (-1/8)(x - 9)
y + 7 = (-1/8)x + 1.125
Subtract 7 from both sides
y = -1/8x - 5.875
4 0
2 years ago
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