It would be 50,000 since the 5 in the other number is in the thousands place so just multiply that by 10 in place value.
The expressions have the same expansion I'd say because the pairs 2 and 30, 3 and 20, and 4 and 15 because they are all equivalent to 60 because they are all factors of 60.
Same goes with the other pairs, because they are all equivalent to 48 because they are all factors of 48.
Option is B) y-3x=0 represents a proportional relationship between the x and y values
Explanation:
Case 1 = y+4=3x
From the above equation we can see that if we change the value of x, the value of y does not changes by proportionality due to the presence of 4 .
Case 2: y-3x=0
From the above equation we can see that if we change the value of x, the value of y changes by proportionality.
Hence the correct option is B.
Case 3 = y+5x=6
From the above equation we can see that if we change the value of x, the value of y does not changes by proportionality due to the presence of 6.
Case 4 = y+1/4×x=2
From the above equation we can see that if we change the value of x, the value of y does not changes by proportionality due to the presence of 2.
Answer:
Answer:
15% off 212.5
30% off 175$
Step-by-step explanation:
15+15=30 so
250/100=2.5
2.5x30=75
250-75
Answer:
, graph is there for reference.
Step-by-step explanation:
Given,
is the number of math problem Lucy solved.
is the number of pages she read.
She can do each math problem in 
minutes, therefore she can solve number of questions into 
minutes.
She can read each page in 
minutes, therefore she can read pages in 2.5y minutes.
As per given detail,
equation 1.
And,
It is given that number of math problems Lucy solved is 3 times the number of pages she read.
equation 2.
We need to find and intercept of each of the equation to graph them.
For 
put y=0
We will get 
Thus the point is 
Let us find 
by assuming 
we get 
Thus the point is 
Join these two points.
Similarly considering the other equation
Here x-intercept would be at 
We will get
Thus the point is 
Let us assume on more point, say 
, we get 
Thus the point is 
Join these two points.
We will get a point of intersection at 
Thus 
and 
