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irinina [24]
3 years ago
6

(4p2 - 5p - 4) + (5p2 - 4-2p)​

Mathematics
2 answers:
Rasek [7]3 years ago
5 0

Answer:

9p^2 - 7p - 8

Hope this helps! Can I have BRAINLIEST please?

Strike441 [17]3 years ago
4 0

Answer:

Answer = 11p - 8

Step-by-step explanation:

(4px2 - 5p - 4) + (5px2 - 4 -2p)

(8p - 5p - 4) + (10p-4 - 2p)

(3p - 4) + (10p -4 -2p)

3p - 4 + 8p - 4

3p + 8p = 11p  

4+4 = 8

Answer 11p - 8

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Beginning with the function y = sin x, which would have range from -1 to 1 and period of 2pi:
Vertical compression of 1/2 compresses the range from -1/2 to 1/2
Phase shift of pi/2 to the left
Horizontal stretch to a period of 4pi, as the crests are at -4pi, 0, 4pi
Vertical shift of 1 unit up moves the range to 1/2 to 3/2
So the first choice looks like a good answer.
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3 years ago
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What was the percent increase of China's
Rom4ik [11]

The percentage increase China's population from 1970 to 1995 is: 56.25%.

<h3>How to Calculate Percentage Increase?</h3>

Percentage increase = (Final Value - Original Value)/Original value × 100.

Given the following:

Original value = 0.8 billion

Final Value = 1.25 billion

Final Value - Original Value = 1.25 - 0.8

Final Value - Original Value = 0.45

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2 years ago
When a principal amount, P, is invested at an annual interest rate,r, and compounded n times per
romanna [79]

Answer:

2

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3 years ago
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In a certain clinical study, 15% of participants were classified as heavy smokers, 25% as light-smokers, and the rest as non-smo
Natasha_Volkova [10]

Answer:

There is a 28.57% probability that a randomly selected participant who died by the end of the study was a non-smoker.

Step-by-step explanation:

We have the following probabilities:

A 15% probability that a participant is classified as a heavy smoker.

A 25% probability that a participant is classified as a light smoker.

A 100% - 25% - 15% = 60% probability that a participant is classified as a non smoker.

A x% probability that a non smoker dies.

A 3x% probability that a light smoker dies.

A 5x% probability that a heavy smoker dies.

This can be formulated as the following problem:

What is the probability of B happening, knowing that A has happened.

It can be calculated by the following formula

P = \frac{P(B).P(A/B)}{P(A)}

Where P(B) is the probability of B happening, P(A/B) is the probability of A happening knowing that B happened and P(A) is the probability of A happening.

This problem is:

What is the probability of the participant being a non-smoker, given that he died?

P(B) is the probability that the participant is a non smoker. So

P(B) = 0.6

P(A/B) is the probability that the participant dies, given that he is a non smoker. So:

P(A/B) = x

P(A) is the probability that the participant dies:

P(A) = P_{1} + P_{2} + P_{3}

P_{1} is the probability that a heavy smoker is selected and that he dies. So:

P_{1} = 0.15*5x = 0.75x

P_{2} is the probability that a light smoker is selected and that he dies. So:

P_{2} = 0.25*3x = 0.75x

P_{3} is the probability that a non-smoker is selected and that he dies. So:

P_{3} = 0.60*x = 0.60x

The probability that a participant dies is:

P(A) = P_{1} + P_{2} + P_{3} = 0.75x + 0.75x + 0.60x = 2.10x

The probability of the participant being a non-smoker, given that he died, is:

P = \frac{P(B).P(A/B)}{P(A)} = \frac{0.6x}{2.10x} = \frac{0.6}{2.10} = 0.2857

There is a 28.57% probability that a randomly selected participant who died by the end of the study was a non-smoker.

7 0
3 years ago
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