With ϕ ≈ 1.61803 the golden ratio, we have 1/ϕ = ϕ - 1, so that
![I = \displaystyle \int_0^\infty \frac{\sqrt[\phi]{x} \tan^{-1}(x)}{(1+x^\phi)^2} \, dx = \int_0^\infty \frac{x^{\phi-1} \tan^{-1}(x)}{x (1+x^\phi)^2} \, dx](https://tex.z-dn.net/?f=I%20%3D%20%5Cdisplaystyle%20%5Cint_0%5E%5Cinfty%20%5Cfrac%7B%5Csqrt%5B%5Cphi%5D%7Bx%7D%20%5Ctan%5E%7B-1%7D%28x%29%7D%7B%281%2Bx%5E%5Cphi%29%5E2%7D%20%5C%2C%20dx%20%3D%20%5Cint_0%5E%5Cinfty%20%5Cfrac%7Bx%5E%7B%5Cphi-1%7D%20%5Ctan%5E%7B-1%7D%28x%29%7D%7Bx%20%281%2Bx%5E%5Cphi%29%5E2%7D%20%5C%2C%20dx)
Replace
:

Split the integral at x = 1. For the integral over [1, ∞), substitute
:

The integrals involving tan⁻¹ disappear, and we're left with

Answer:
2 cm
Step-by-step explanation:
h = 14 cm
Curved surface area of a right circular cylinder = 88 cm²
2πrh = 88

Diameter = 2 * r = 2 * 1 = 2 cm
Answer:
12 m
Step-by-step explanation:
The path of a football has been modeled by the equation:

where h represents the height and d represents the horizontal distance.
When the ball lands, it means that its height is back at 0 metres. This means that we have to find horizontal distance, d, when height, h, is 0.
=> 


∴ d = 0 m
and
10d - 120 = 0
=> d = 120 / 10 = 12 m
There are two solutions for d when h = 0 m.
The first solution (d = 0 m) is a case where the ball has not been thrown at all. This means the ball has not moved away from the football player and it is still on the ground.
The second solution is the answer to our problem (d = 12 m). The ball lands at a horizontal distance of 12 m
Answer:

Step-by-step explanation:
we know that
The <u>Triangle Inequality Theorem</u> states that the sum of any 2 sides of a triangle must be greater than the measure of the third side
so
Applying the Theorem
case 1) 



case 2) 


-----> rewrite
case 3) 



therefore

Answer is B
total cost = $30 + 0.5 *(miles driven)
.................