Answer:
2.5%WATER IS INSIDE CELL
OUTER CELL WATER WILL MOVE
IT WILL SWELL
IT'S HYPOTONIC SOLUTION
Answer:
Glutamate is the primary excitatory transmitter in the central nervous system. Conversely, a major inhibitory transmitter is its derivative γ-aminobutyric acid (GABA), while another inhibitory neurotransmitter is the amino acid called glycine, which is mainly found in the spinal cord.
Explanation:
Meiosis I
Prophase I - homologous chromosomes form a tetrad, where they begin cross-over through the process of synapses.
Metaphase - homologous chromosomes then align along the metaphase plate.
Anaphase I - spindles then separate the homologous chromoses, pulling them to opposite poles of the cell
Telephase I - the cell creates a cleavage burrow inwhich the cell divides into two new cells with 46 chromosomes in the process of cytokinesis
Meiosis II
The same as mitosis
Prophase II - Nuclear envelope disintegrates, Sister chromatids migrate towards the metaphase plate.
Metaphase II - Sister chromatids align along the plate by their centromere.
Anaphase II- spindles pull the chromatin to opposites poles
Telephase II- cleavage burrow forms and cells seperate through cytokinesis
end result
4 haploid gametes are formed
Answer:
9 out of 16 offsprings
Explanation:
This question involves two genes in guinea pig; one coding for coat texture and the other for coat color. The alleles for smooth coat (S) and black coat (B) are dominant over rough coat (s) and white coat (b).
In this question, two heterozygous guinea pigs were crossed i.e. SsBb × SsBb. The gametes produced by each parent is as follows: SB, Sb, sB, sb. Using these gametes in a punnet square (see attached image), the proportion of offsprings will be:
Smooth black coat (S_B_) = 9
Smooth white coat (S_bb) = 3
Rough black coat (ssB_) = 3
Rough white coat (ssbb) = 1
Hence, according to this question, 9 out of 16 offsprings will have a smooth black coat on average.
B, because it's not an advantage for something to be expensive and time consuming
