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BartSMP [9]
2 years ago
6

The result of the Hershey-Chase experiment was that radioactivity could be detected inside the bacterial cells when they were in

fected by
bacteriophages marked with phosphorus-32.
What did the investigators conclude from this result?
A. Bacteriophages inject DNA into the bacterial cells.
B. Bacteriophages inject protein into the bacterial cells.
C. Bacteriophages inject carbohydrates into the bacterial cells.
D. Bacteriophage absorb DNA from bacterial cells.
Biology
1 answer:
ehidna [41]2 years ago
6 0

Answer:

i belive that it is option a

Explanation:

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3 meter / second square.

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4 0
2 years ago
Which comparisons of Trial A (no immunity) and
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Answer:

1.

3.

4.

Explanation:

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If compared, trial C will have less infected people than trial A because people in trial A has no immunity and people in trial C have 50% of immunity, so only fewer people will get infected even after six point of contact.

As percentage of immune people (trial C) is 50, so there are equal chances of immunity and non-immunity. there are three reasons of infection that include source, susceptible person and transmission. source and susceptible person can be the reason of infection in some non-immune people but the transmission reason can vary. s<em>o, there is probability that three nonimmune people lie under transmission reason and are not coming in contact with infected  people, medical equipment or environment, that causes infection and those three people are not getting infected.</em>

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5 0
3 years ago
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