A:B = 2:3
A=126
B=?
126/2=63
63x3=189
A=126
B=189
A:B = 126:189
Answer:
Measure of angle A is 65 degrees and measure of angle B is 37 degrees.
Step-by-step explanation: First add all of the degrees of excluding x (4+(-9)) which is -5. Then subtract that from 180 since that is the sum of all the angles in a triangle which gives you 185. Then divide it by the number of "x's" that there are which is 5 which gives you 37. So angle B is x which is 37 degrees and angle a is 2(37)-9 which is 65 degrees. Hope this helps.
This is a 45-45-90 triangle and the ratios of the sides are 1 : 1 : sqrt2 where sqrt2 is the length of the hypotenuse ( longest side)
So the measure of x = 12 sqrt2 which is the first choice.
Sj ebfbruejnxjjendnzjejnzzkijeskao
The area bounded by the 2 parabolas is A(θ) = 1/2∫(r₂²- r₁²).dθ between limits θ = a,b...
<span>the limits are solution to 3cosθ = 1+cosθ the points of intersection of curves. </span>
<span>2cosθ = 1 => θ = ±π/3 </span>
<span>A(θ) = 1/2∫(r₂²- r₁²).dθ = 1/2∫(3cosθ)² - (1+cosθ)².dθ </span>
<span>= 1/2∫(3cosθ)².dθ - 1/2∫(1+cosθ)².dθ </span>
<span>= 9/8[2θ + sin(2θ)] - 1/8[6θ + 8sinθ +sin(2θ)] .. </span>
<span>.............where I have used ∫(cosθ)².dθ=1/4[2θ + sin(2θ)] </span>
<span>= 3θ/2 +sin(2θ) - sin(θ) </span>
<span>Area = A(π/3) - A(-π/3) </span>
<span>= 3π/6 + sin(2π/3) -sin(π/3) - (-3π/6) - sin(-2π/3) + sin(-π/3) </span>
<span>= π.</span>
