Staals half
1 gram left
0.3 grams left
half lives are normally written in years
it goes likt this
![A=P( \frac{1}{2})^ \frac{t}{h}](https://tex.z-dn.net/?f=A%3DP%28%20%5Cfrac%7B1%7D%7B2%7D%29%5E%20%5Cfrac%7Bt%7D%7Bh%7D%20%20)
A=final amount
P=initila amount
t=time elapsed
h=time half life is (same units as time)
let's use days as the units of time
we are given
initial amount=1gram
final amount=0.3gram
time=4 days
so
![0.3=1( \frac{1}{2})^ \frac{4}{h}](https://tex.z-dn.net/?f=0.3%3D1%28%20%5Cfrac%7B1%7D%7B2%7D%29%5E%20%5Cfrac%7B4%7D%7Bh%7D%20%20)
solve for h
![0.3=( \frac{1}{2})^ \frac{4}{h}](https://tex.z-dn.net/?f=0.3%3D%28%20%5Cfrac%7B1%7D%7B2%7D%29%5E%20%5Cfrac%7B4%7D%7Bh%7D%20%20)
take the ln of both sides
![ln(0.3)=ln( \frac{1}{2})^ \frac{4}{h}](https://tex.z-dn.net/?f=ln%280.3%29%3Dln%28%20%5Cfrac%7B1%7D%7B2%7D%29%5E%20%5Cfrac%7B4%7D%7Bh%7D%20%20)
![ln(0.3)=\frac{4}{h}ln( \frac{1}{2})](https://tex.z-dn.net/?f=ln%280.3%29%3D%5Cfrac%7B4%7D%7Bh%7Dln%28%20%5Cfrac%7B1%7D%7B2%7D%29%20%20%20)
times both sides by h
![hln(0.3)=4ln( \frac{1}{2})](https://tex.z-dn.net/?f=hln%280.3%29%3D4ln%28%20%5Cfrac%7B1%7D%7B2%7D%29%20%20%20)
divide both sides by ln(0.3)
![h= \frac{4ln( \frac{1}{2}) }{ln(0.3)}](https://tex.z-dn.net/?f=h%3D%20%5Cfrac%7B4ln%28%20%5Cfrac%7B1%7D%7B2%7D%29%20%7D%7Bln%280.3%29%7D%20)
use calculator
h=2.30287
3 sig figs
h=2.303 days
Answer: EQUATION: p-6=-14 ANSWER: p=-8
Step-by-step explanation:
Just simply add 6 to both sides so p can be by by itself. -14+6=-8
Hope this helped you! ^_^
The answer is symmetric because it’s equal