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Brut [27]
2 years ago
10

Addison and Kelsey are running on a path modeled by x2 + y2 – 14x – 16y – 287 = 0, where the distance is in meters. What is the

maximum distance between the runners at any given time?
20 meters
32 meters
40 meters
140 meters
Mathematics
1 answer:
Simora [160]2 years ago
6 0

Answer:

40 meters

Step-by-step explanation:

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Can you please help me do find a resolution for these equations
rusak2 [61]

Answer:

x=-5

Step-by-step explanation:

I did a for #42

2(x-5)=3x+5

simplify

2x-10=3x+5

subtract 2x from both sides

-10=3x+5

subtract 5 from both sides

-15=3x

divide both sides by 3

-5=x

6 0
3 years ago
you deposit $1500 in an account that pays 5% annual interest compounded continuously what is the balance after 6 years.
Gemiola [76]
Hello kiddio lets figure this out!

The formula for simple interest is I = P*R*T where I = interest, P = Principal (original amount), R is the rate as a decimal, and T is time in years.  So I = 1500*(.05)*6 = 1500*(0.30) = $450.  The total amount you have after 6 years is the amount you started with ($1500) plus the interest ($450) which is $1950.   The formula for yearly compounding is  A = P(1 + r)t   where   A = Accumulated or final amount  P = Principal ($1500) r = interest rate as a decimal (0.05)t = time (6 years)   A = 1500*(1 + 0.05)6 = 1500*(1.05)6 = $2010.14  

Have a nice day
3 0
3 years ago
Solve P = P - C for C
Rina8888 [55]

Answer:

c=0

Step-by-step explanation:

5 0
4 years ago
Read 2 more answers
Find (f • g) when f(x) = x^2 + 5x + 6 and g(x) = 1/x+3
Nikitich [7]

Answer:

option D

Step-by-step explanation:

f(x) = x^2 + 5x + 6

g(x)= \frac{1}{x+3}

(fog)(x) = f(g(x))

Plug in g(x) in f(x)

We plug in 1/x+3 in the place of x  in f(x)

f(g(x))= f(\frac{1}{x+3})= (\frac{1}{x+3})^2 + 5(\frac{1}{x+3}) + 6

To simplify it we take LCD

LCD is (x+3)(x+3)

\frac{1}{(x+3)(x+3)}+5\frac{1*(x+3)}{(x+3)(x+3)}+\frac{6(x+3)(x+3)}{(x+3)(x+3)}

\frac{1}{x^2+6x+9}+\frac{(5x+15)}{x^2+6x+9}+\frac{6x^2+36x+54}{x^2+6x+9}

All the denominators are same so we combine the numerators

\frac{1+5x+15+6x^2+36x+54}{x^2+6x+9}

\frac{6x^2+41x+70}{x^2+6x+9}

Option D is correct

8 0
3 years ago
Read 2 more answers
47. What is the 12th term of the geometric sequence?
GrogVix [38]

Answer:

A

Step-by-step explanation:

The rule is 2x.

So 3,6,12,24,48,96,192,384,768,1536,3072,6144,12288,....

The question asked for the 12th term so 6144.

5 0
3 years ago
Read 2 more answers
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