When solving an equation with an absolute value term, you make two separate equations ans solve for x:
Equation 1: |4x-3|-5 = 4
1st add 5 to both sides:
|4x-3| = 9
Remove the absolute value term and make two equations:
4x-3 = 9 and 4x - 3 = -9
Solving for x you get X = 3 and x = -1.5
When you replace x with those values in the original equation the statement is true so those are two solutions.
Do the same thing for equation 2:
|2x+3| +8 = 3
Subtract 8 from both sides:
|2x+3| = -5
Remove the absolute value term and make two equations:
2x +3 = -5
2x+3 = 5
Solving for x you get -1 and 4, but when you replace x in the original equation with those values, the statement is false, so there are no solutions.
The answer is:
C. The solutions to equation 1 are x = 3, −1.5, and equation 2 has no solution.
Answer:
230 were sold at the door
170 were sold in advance
Step-by-step explanation:
x=at door y=in advance
x+y=400
3x+2y=1030
y=-x+400
2y=-3x+1030
y=-3/2x+515
-x+400=-3/2x+515
x=230 y=170
So what you asked this is what I got
x(y) = 4.5
If x= 0.5 then
0.5(y) = 4.5
y=9
x(y) = 4.5
10(y) = 4.5
y= 0.45
hope this helps :)
Expand it, so you will get 9x^2 + 24x + 16
