30+7+200, 7+30+200, 230+7, 207+30 200+37
Answer: 620≥ 427.57+ 11.38(4)+ (31.41) +57.75x
Step-by-step explanation:
So our limit is the 620$ that he has to spend. We know for a fact that the bike costs about 427.57 dollars. 4 $11.38 reflectors are purchased as well as gloves for 31.41. Now however many outfits he can purchase cannot exceed or go over his money limit of 620 so the variable (x) represents how many outfits he can buy without going over.
Answer:
Step-by-step explanation:
The foci are horizontally aligned.
horizontal ellipse:
(x-h)²/a² + (y-k)²/b² = 1
center (h,k)
vertices (h±a,k)
length of minor axis = 2b
foci (h±c,k), c² = a²-b²
Apply your data and solve for h, k, a, and b.
foci (±3√19, 6)
h = 0
k = 6
Length of minor axis = 2b = 10
b = 5
foci (h±3√19, 6)
c = 3√19
c³ = a² - b²
171 = a² - 25
a² = 196
x²/196 + (y-6)²/25 = 1
If 30 is half price, then what is full price?
You can set up this problem like this:
30 = x/2
OR
30 = (1/2)x
where x is the full price.
To solve, simply multiply each half by 2:
2(30) = 2((1/2)x)
<u>x = $60</u>
If it has a constant slope that means it makes a straight line making it linear
