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3 years ago

15

A credit card issuer offers an APR. of 22.08% and compounds interest daily. Which is it most likely to advertise, its APR or it’

s effective Interest rate?

2 answers:

Alex3 years ago

8 0

<span>Answer: The credit card issuer will show APR which is 22.08% and not effective rate of interest. This is because Effective rate, when calculated with the formula given below will come as 24.67% which is 2.59% more and hence will make customers feel that they are paying more. r = [ { (1+ i / n) ^ (n) } - 1] * 100 Where i = APR/100 n = number of compounding periods which is 365 in this case as compounding is done daily. [ { (1+ 0.2208 / 365) ^ (365) }- 1] * 100</span>

Leto [7]3 years ago

5 0

Answer:

It's APR, because it's 2.62% less than its effective interest rate.

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Reagan scored 1140 on the SAT. The distribution of SAT scores in a reference population is normally distributed with mean 1000 a

krok68 [10]

Answer:

Jessie scored higher than Reagan.

Step-by-step explanation:

We are given that Reagan scored 1140 on the SAT. The distribution of SAT scores in a reference population is normally distributed with mean 1000 and standard deviation 100.

Jessie scored 30 on the ACT. The distribution of ACT scores in a reference population is normally distributed with mean 17 and standard deviation 5.

For finding who performed better on the standardized exams, we have to calculate the z-scores for both people.

1. <u>Finding z-score for Reagan;</u>

Let X = distribution of SAT scores

SO, X ~ Normal( $\mu=1000, \sigma^{2}=100^{2}$ )

The z-score probability distribution for the normal distribution is given by;

Z = $\frac{X-\mu}{\sigma}$ ~ N(0,1)

where, $\mu$ = population mean = 1000

$\sigma$ = standard deviation = 100

Now, Reagan scored 1140 on the SAT, that is;

z-score = $\frac{1140-1000}{100}$ = 1.4

2. <u>Finding z-score for Jessie;</u>

Let X = distribution of ACT scores

SO, X ~ Normal( $\mu=17, \sigma^{2}=5^{2}$ )

The z-score probability distribution for the normal distribution is given by;

Z = $\frac{X-\mu}{\sigma}$ ~ N(0,1)

where, $\mu$ = population mean = 17

$\sigma$ = standard deviation = 5

Now, Jessie scored 30 on the ACT, that is;

z-score = $\frac{30-17}{5}$ = 2.6

This means that Jessie scored higher than Reagan because Jessie's standardized score was 2.6, which is 2.6 standard deviations above the mean and Reagan's standardized score was 1.4, which is 1.4 standard deviations above the mean.

6 0

3 years ago

B/5>-1<br> Solve the inequality. Graph and check the solution.

Usimov [2.4K]

Answer:

b>-5

Step-by-step explanation:

$\frac{b}{5} > - 1$

Multiply by 5 to isolate b.

$b > - 5$

If you graph this on a line, it would be a hollow point facing the right, since it's any number greater than five, not including 5.

If you put any number greater than -5, you'll output greater than - 1.

4 0

3 years ago

Determine whether each function is an example of exponential growth or decay. Then, find the y -intercept. y=25/7(7/5) x

Olenka [21]

y = 25x / 5 is each function is an example of exponential growth or decay.

What does exponential growth look like in math?

A typical illustration of exponential expansion is population increase. Take a population of bacteria as an example. It seems sense that the rate of population increase would be inversely correlated with the population's size.
After all, the number of bacteria grows more quickly the more there are for them to reproduce.

y= 25/7(7/5) x

y = 25/5 x

y = 25x / 5

Learn more about exponential growth

brainly.com/question/11487261

#SPJ4

7 0

1 year ago

Given the following trigonometric ratio, enumerate the meaning ratio

Likurg_2 [28]

Answer:

The trigonometric ratios are presented below:

$\sin \theta = \frac{AC}{\sqrt{AC^{2} + BC^{2}}}$

$\cos \theta = \frac{BC}{\sqrt{AC^{2} + BC^{2}}}$

$\cot \theta = \frac{BC}{AC}$

$\sec \theta = \frac{\sqrt{AC^{2}+BC^{2}}}{BC}$

$\csc \theta = \frac{\sqrt{AC^{2}+BC^{2}}}{AC}$

Step-by-step explanation:

From Trigonometry we know the following definitions for each trigonometric ratio:

Sine

$\sin \theta = \frac{y}{h}$ (1)

Cosine

$\cos \theta = \frac{x}{h}$ (2)

Tangent

$\tan \theta = \frac{\sin \theta}{\cos \theta} = \frac{y}{x}$ (3)

Cotangent

$\cot \theta = \frac{\cos \theta}{\sin \theta} = \frac{x}{y}$ (4)

Secant

$\sec \theta = \frac{1}{\cos \theta} = \frac{h}{x}$ (5)

Cosecant

$\csc \theta = \frac{1}{\sin \theta} = \frac{h}{y}$ (6)

Where:

$x$ - Adjacent leg.

$y$ - Opposite leg.

$h$ - Hypotenuse.

The length of the hypotenuse is determined by the Pythagorean Theorem:

$h = \sqrt{x^{2}+y^{2}}$

If $y = AC$ and $x = BC$ , then the trigonometric ratios are presented below:

$\sin \theta = \frac{AC}{\sqrt{AC^{2} + BC^{2}}}$

$\cos \theta = \frac{BC}{\sqrt{AC^{2} + BC^{2}}}$

$\cot \theta = \frac{BC}{AC}$

$\sec \theta = \frac{\sqrt{AC^{2}+BC^{2}}}{BC}$

$\csc \theta = \frac{\sqrt{AC^{2}+BC^{2}}}{AC}$

6 0

3 years ago

On the number line bug A is moving in the positive direction from the point 0, and a bug B is moving in the negative direction f

kumpel [21]

Answer:

x =6t

y = - 5t

6 0

3 years ago