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3 years ago

A diagonal of a cube measures square root 150cm. the diagonal of a face measures 10cm

Mathematics

1 answer:

leonid [27]3 years ago

6 0

Answer: The finial answer is 15.8

This problem is just one about triangles! All of the faces of the cube are perpendicular to their adjacent faces, so the diagonal of one of the face will be a right angle with the edge of the cube. Thus, you can create a right triangle. Finally, use the Pythagorean Theorem to solve for x, the length of the side of the cube.

Step-by-step explanation:

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Solve 3x2 + 4x = 2. TEACH me how to solve this.. I know what to do once I have it in the right forum... but I do not understand

sertanlavr [38]

So if it is 3x^2+4x=2 then
set one side to zero
subtract 2 from both sides
3x^2+4x-2=0
this is not factorable by normal means so use quadratic formula which is if you have the equation in ax^2+bx+c=0 form you can solve for x if you put it into this equation quadratic formula $x=\frac{-b+ \sqrt{b^2-4ac} }{2a} or \frac{-b- \sqrt{b^2-4ac} }{2a}$ so if you were to input it into this equation you would get
a=3
b=4
c=-2

the solution is $x= \frac{-2+ \sqrt{10} }{3} or \frac{-2- \sqrt{10} }{3}$
the answer is C

7 0

3 years ago

Read 2 more answers

What is the rate of change from x = n to x = 2n?

puteri [66]

Answer:

$\dfrac{-8}{\pi}$

Step-by-step explanation:

The rate of change of the function f(x) from point $x_1$ to point $x_2$ can be calculated using formula

$\dfrac{f(x_2)-f(x_1)}{x_2-x_1}$

Given

$x_1=\pi\\ \\x_2=2\pi$

From the graph of the function

$f(x_1)=f(\pi)=4\\ \\f(x_2)=f(2\pi)=-4$

So, the rate of change is

$\dfrac{f(x_2)-f(x_1)}{x_2-x_1}=\dfrac{-4-4}{2\pi -\pi}=\dfrac{-8}{\pi}$

5 0

3 years ago

Solve for X.<br><br>I've tried and it's confusing I'm not really that great at geometry

Nutka1998 [239]

Set as a proportion
16 = 12
------------------
5x+2 24

cross multiply
12(5x+2) = 16 * 24
60x +24 = 384
60x +24-24 = 384-24
60x =360
60x/60=360/60
x =6

To figure AB plug 6 into 5x+2
5x +2
5(6) + 2
30+2
32
AB = 32

4 0

3 years ago

What is the length of the conjugate axis? (y-2)^2/16 -(x+1)^2/144=1

aleksandr82 [10.1K]

Answer: 24

A hyperbola is the locus of a point in a plane which moves in the plane in such a way that the ratio of its distance from a fixed point in the same plane to its distance from a fixed line is always constant, which is always greater than unity.

the fixed point is called the focus and the fixed line is directrix and the ratio is the eccentricity.

The general equation for the vertical hyperbola is

[ (y-k)^2 / a^2 ] – [ (x-h)^2 / b^2 ] = 1

The conjugate axis of the vertical hyperbola is y = k

Length of the conjugate axis = 2b

According to the question k = 2, h = -1, a = 4, b = 12

Length of the conjugate axis = 2b = 2 * 12 = 24

Learn more about hyperbola here :

brainly.com/question/3351710

#SPJ9

7 0

2 years ago