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alexgriva [62]
3 years ago
9

a collector has 80 jackeys and 125 shirts she wants to maintain ratio in her collection but she needs to sell some of her items

if she sells 16 jackets how many total items should she sell from her collection​
Mathematics
1 answer:
Irina18 [472]3 years ago
8 0

Answer:

25

Step-by-step explanation:

Well, we need to simplify this. we have a ratio of 80:125.

As these numbers end in either 0 or 5, we know they are divisible by 5.

By dividing these by five, our ratio becomes 16:25.

As we have 16 jackets, we know we must need to sell 25 jackets to maintain the ratio.

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Please help me on this problem
Anna71 [15]

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The pairs of integer having two real solution forax^{2} -6x+c = 0 are

  1. a = -4, c = 5
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Step-by-step explanation:

Given

ax^{2} -6x+c = 0

Now we will solve the equation by putting all the 6 pairs so we get the  following

-3x^{2} -6x-5 = 0 for a = -3 , c=-5

-4x^{2} -6x+5 = 0 for a = -4 , c=5

1x^{2} -6x+6 = 0 for a = 1 , c=6

2x^{2} -6x+3 = 0 for a = 2 , c=3

3x^{2} -6x+3 = 0 for a = 3 , c=3

5x^{2} -6x+4 = 0 for a = 5 , c=4

The above  all are Quadratic equations inn general form ax^{2} +bx+c=0

where we have a,b and c constant values

So for a real Solution we must have

Disciminant , b^{2} -4\timesa\timesc \geq 0

for a = -3 , c=-5 we have

Discriminant =-24 which is less than 0 ∴ not a real solution.

for a = -4 , c=5 we have

Discriminant = 116 which is greater than 0 ∴ a real solution.

for a = 1 , c=6 we have

Discriminant =12 which is greater than 0 ∴ a real solution.

for a = 2 , c=3 we have

Discriminant =12 which is greater than 0 ∴ a real solution.

for a = 3 , c=3 we have

Discriminant =0 which is equal to 0 ∴ a real solution.

for a = 5 , c=4 we have

Discriminant =-44 which is less than 0 ∴ not a real solution.

7 0
3 years ago
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