3 years ago

The ages of five friends are 20,31,28,31 and 25. How many of the friends are older than the average (arithmetic mean) age?

1 answer:

7 0

Answer:

3 friends

Step-by-step explanation:

The mean age is 27 so 3 friends are above that age.

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Neporo4naja [7]

We have been given that a store manager paid $95 for an item and set the selling price at $116.85. We are asked to find the percent mark-up.

We will use percent increase formula to solve our given problem.

$\text{Percent increase}=\frac{\text{Final}-\text{Initial}}{\text{Initial}}\times 100\%$

$\text{Percent increase}=\frac{\$116.85-\$95}{\$95}\times 100\%$

$\text{Percent increase}=\frac{\$21.85}{\$95}\times 100\%$

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Alecsey [184]

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sertanlavr [38]

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oksano4ka [1.4K]

Answer:

mean; the average of George's scores is the mean = 83.4

Step-by-step explanation:

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