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3 years ago

The ages of five friends are 20,31,28,31 and 25. How many of the friends are older than the average (arithmetic mean) age?

Mathematics

1 answer:

FromTheMoon [43]3 years ago

7 0

Answer:

3 friends

Step-by-step explanation:

The mean age is 27 so 3 friends are above that age.

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3 years ago

Joel made some muffins. He gave 1/4 of of the muffins to a neighbor. He took 3/8 of the muffins to school. What fraction of the

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3 years ago

A taxi charges a flat rate of $1.75, plus an additional $0.65 per mile. If Erica has at most $10.20 to spend on a

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2 years ago

Expres each of the folowing as a single matrix.

Elden [556K]

Answer:

$\left[\begin{array}{cc}6&-3\\10&-1\end{array}\right]+\left[\begin{array}{cc}-2&8\\3&-12\end{array}\right]=\left[\begin{array}{cc}4&5\\13&-13\end{array}\right]$

Step-by-step explanation:

If you have two matrices:

$A=\left[\begin{array}{cc}a&b\\c&d\end{array}\right]\\and\\B=\left[\begin{array}{cc}e&f\\g&h\end{array}\right]\\\\\\A+B=\left[\begin{array}{cc}a+e&b+f\\c+g&d+h\end{array}\right]$

We have:

$A=\left[\begin{array}{cc}6&-3\\10&-1\end{array}\right]\\and\\B=\left[\begin{array}{cc}-2&8\\3&-12\end{array}\right]$

And we need to express as a single matrix:

$A+B=\left[\begin{array}{cc}6&-3\\10&-1\end{array}\right]+\left[\begin{array}{cc}-2&8\\3&-12\end{array}\right]\\\\\\A+B=\left[\begin{array}{cc}6+(-2)&-3+8\\10+3&-1+(-12)\end{array}\right]\\\\\\A+B=\left[\begin{array}{cc}6-2&5\\13&-1-12\end{array}\right]\\\\\\A+B=\left[\begin{array}{cc}4&5\\13&-13\end{array}\right]$

The answer is:

$\left[\begin{array}{cc}6&-3\\10&-1\end{array}\right]+\left[\begin{array}{cc}-2&8\\3&-12\end{array}\right]=\left[\begin{array}{cc}4&5\\13&-13\end{array}\right]$

It is expressed as a single matrix.

8 0

3 years ago