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ELEN [110]
3 years ago
15

Solve for each inequality. 8 ≤ x - (-14) 31 ≥ b - (-18) -5 < n + (-1)

Mathematics
1 answer:
Gennadij [26K]3 years ago
5 0

Answer:

8 \leqslant x - ( - 14) \\ 8 \leqslant x + 14 \\ 8 - 14 \leqslant x + 14 - 14 \\  - 6 \leqslant x \\ x \geqslant  - 6

___o__o__

31 \geqslant b - ( - 18) \\ 31 \geqslant b + 18 \\ 31 - 18 \geqslant b + 18 - 18 \\ 13 \geqslant b \\ b \leqslant 13

__o__o__

- 5 < n + ( - 1) \\  - 5 < n - 1 \\  - 5 + 1 < n - 1 + 1 \\  \\  - 4 < n \\ n >  - 4

I hope I helped you^_^

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The length and width of a rectangle are measured as 27 cm and 50 cm, respectively, with an error in measurement of at most 0.1 c
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Answer:

7.7cm

Step-by-step explanation:

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The area of the rectangle with error will be expressed as A = LdW + WdL

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A = 2.7+5.0

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3 years ago
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Answer:

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3 years ago
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Answer:

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equivalence relation R on {1,2,3}

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2.For transitive, it must satisfy: if (x,y)∈R then (y,x)∈R

3. For symmetric, it must satisfy: if (x,y)∈R,(y,z)∈R then (x,z)∈R

Since (1,1),(2,2),(3,3) must be there is R, (1,2),(2,1),(2,3),(3,2),(1,3),(3,1). By symmetry,

we just need to count the number of ways in which we can use the pairs (1,2),(2,3),(1,3) to construct equivalence relations.

This is because if (1,2) is in the relation then (2,1) must be there in the relation.

the relation will be an equivalence relation if we use none of these pairs (1,2),(2,3),(1,3) . There is only one such relation: {(1,1),(2,2),(3,3)}

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{(1,1),(2,2),(3,3),(1,3),(3,1)}

{(1,1),(2,2),(3,3),(2,3),(3,2)}

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